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topjm [15]
3 years ago
8

Please help me!! I will mark brainliest

Mathematics
1 answer:
Annette [7]3 years ago
6 0

I drew it out below (don't you just love my effort? XD)

You're gonna use the sine trig function to find the length of the shadow

sin26 / 1 = 43 / x; now you cross multiply

sin26 x = 43; divide both sides by sin26

x = 43 / sin26

x = 98 which is the shadow

Hope this helps!

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A plane is scheduled to complete a 1,792-mile flightin 3.5 hours. In order to complete the trip on time, what should be the plan
deff fn [24]

Answer:

  512 mph

Step-by-step explanation:

The relevant relation is ...

  speed = distance/time

  speed = 1792 mi/(3.5 h) = 512 mi/h

The plane's average rate of speed should be 512 miles per hour.

5 0
3 years ago
Kyle is stringing a necklace with beads he puts black beads on 5/8 of the string and white beads on 1/4 of the string Kyle think
Alexeev081 [22]

Answer:Kyle’s claim is not reasonable

Step-by-step explanation:

Total length of the string of the necklace that Kyle covered with black beads is 5/8.

Total length of the string of the necklace that Kyle covered with white beads is 1/4.

Total length of the string of the necklace that Kyle covered with black beads and white beads is would be

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It means that he covered more than 6/12. Kyle's claim was wrong

3 0
3 years ago
Find the local maximum and minimum values and saddle point(s) of the function. If you have three-dimensional graphing software,
grandymaker [24]

Solution:

There is no saddle point (DNE). However, there is local maximum at (1, 1/2) for the given function.

Explanation:

we have function of two variables f(x,y)= 9-2x+4y-x^2-4y^2

we will find the values by partial derivative with respect to x,y,xy

f_{x}= -2 -2x

f_{y}= 4 -8y

to find the saddle point we should first find the critical points so equate

-2 -2x=0 and   4 -8y=0

we get x= 1  and y =1/2 so, critical points are (1,1/2)

to find local maximum or minimum we have to find f_{xx},  f_{yy} and f_{xy}

formula is f_{xx} *f_{yy} - f^{2_{xy} } =0

f_{xx} = -2

f_{yy} = -8

f^{2_{xy} } =0

putting values in formula

(-2)*(-8) -0 =16 > 0, and f_{xx}< 0  and f_{yy}<0

so, here we have local maximum

we have no saddle point for this function by using the same formula we used to find extrema.



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-Steel jelly


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