Question

PLEASE HELP

Answer 1

Option A

$4 x^{2}+32 x-80=0$ is the required equation to calculate width of rectangular frame that has a total area of 140 square inches.

Solution:

Given that,

Length of a rectangular frame is given as 2x + 10

Width of the rectangular frame is given as 2x + 6

Total area = 140 square inches

The area of rectangular frame is given as:

$\text {area of rectangle}=\text {length } \times \text {width}$

Plugging in values, we get

$\begin{array}{l}{(2 x+10)(2 x+6)=140} \\\\ {4 x^{2}+12 x+20 x=80} \\\\ {4 x^{2}+32 x-80=0}\end{array}$

This is the required equation to calculate width of rectangular frame

Solve the above quadratic equation to get the value of "x"

$4 x^{2}+32 x-80=0$

Use the quadratic equation formula:

$x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

Here a = 4 ; b = 32 ; c = -80

$x=\frac{-32 \pm \sqrt{32^{2}-4(4)(-80)}}{2(4)}$

$x=\frac{-32 \pm \sqrt{2304}}{8}$

x = 2 or x = -10

Now measurement cannot be negative, so taking the positve value of "x", we can calculate the width

So put "x" = 2

Width of the rectangular frame = 2x + 6 = 2(2) + 6 = 10

Thus the width of frame is 10 inches