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ollegr [7]
2 years ago
8

Scale factor word problem Someone please help me!

Mathematics
1 answer:
natima [27]2 years ago
3 0

1. Niles is making a map of his neighborhood. He uses a scale in which 1 cm = 5 km. The distance between his house and the school is 8.5 km.

How many centimeters will there be between his house and school on the map?

1 cm = 5km

8.5 ÷ 5 = 1.7

There will be 1.7 centimeters between his house and school.

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One more then im done, ty ^^
OleMash [197]

Answer:

5

Step-by-step explanation:

5 0
2 years ago
Write an equation in standard form of the parabola that has the same shape as the graph of f(x)=5x^2or g(x)=-5x^2, but with a gi
pickupchik [31]
F(x)=5x^2 Has minimum (0,0)

g(x) = f(x) + 2 Shifts the graph two units up, then the minimum is 2+0=2.

h(x) = g(x+4) Shifts the graph four units left,  then the minimum is at 0-4 = -4.

Then h(x) = 5(x+4)^2 + 2 has the minimum (-4,2)

And p(x) = -5(x+4)^2 + 2 has the maximum (-4,2)
 
4 0
3 years ago
UPPER AND LOWER BOUNDS - PLEASE HELP!
Marianna [84]
Qn. 1
Lower bound for Zoe's weight = 62 - (1/2) = 62 - 0.5 = 61.5 kg

Qn. 2
Upper bound for length AB = 8.3+ (0.1/2) = 8.3+0.05 = 8.35 cm

Qn. 3
Upper bound for Anu's wight = 83+(0.5/2) = 83+0.25 = 83.25 kg

Qn. 4
Lower bound for length CD = 27-(0.5/2) = 27-0.25 = 26.75 cm

Qn. 5
Upper bound for sides of the hexagon = 3.6+(0.1/2) = 3.6+0.05 = 3.65 cm
Upper bound for the perimeter = upper bound for the sides*6 = 3.65*6 = 21.9 cm

Qn. 6
Perimeter = 4*length => side = Perimeter/4 = 24/4 = 6
Bound = 0.5/4 = 0.125
Lower bound of the length = 6-0.125 = 5.875 cm

Qn. 7
For the area,
Upper bound = 80+(10/2) 80+5 = 85 cm^2
For the length
Upper bound = 12+(1/2) = 12+0.5 = 12.5

Then, upper bound for the width = Upper bound for the area/upper bound for the length = 85/12.5 = 6.8 cm

Qn. 8
Lower bound for the area = 230-(1/2) = 230-0.5 = 229.5 cm^2
Lower bound for the sides of the square = Sqrt(Lower bound of the area) = Sqrt (229.5) = 15.15
Then,
Lower bound of perimeter = 4(Length) = 4*15.15 = 60.6 cm
8 0
3 years ago
Como clasificar por conjuntos ?
PSYCHO15rus [73]

Answer:

yeyes

Step-by-step explanation:

4 0
2 years ago
Qaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa
Kipish [7]

Answer:

32.8 miles

Step-by-step explanation:

Amy is driving to Seattle. Suppose that the remaining distance to drive (in miles) is a linear function of her driving time (in minutes). When graphed, the function gives a line with a slope of -0.95. See the figure below. Amy has 48 miles remaining after 31 minutes of driving. How many miles will be remaining after 47 minutes of driving?

Answer: The general equation of a line is given as y = mx + c, where m is the slope of the line and c is the intercept on the y axis. Given that the slope is -0.95, substituting in the general equation :

y = -0.95x + c

Amy has 48 miles remaining after 31 minutes of driving, to find c, we substitute y = 48 and x = 31. Therefore:

48 = -0.95(31) + c

c = 48 + 0.95(31)

c = 48 + 29.45

c = 77.45

The equation of the line is

y = -0.95x + 77.45

After 47 minutes of driving, the miles remaining can be gotten by substituting x = 47 and finding y.

y = -0.95(47) + 77.45

y = -44.65 + 77.45

y = 32.8 miles

3 0
3 years ago
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