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A cuboid in which the sum of its dimensions is 9 cm., then the sum of its edge lengths - cm. (18 or 27 or 36 or 45)

ser-zykov [4K]

The number of sides or edges on a cuboid are twelve, and the sum of the

edges is the sum of the twelve edges.

The sum of the edge lengths = 36 cm

Reasons:

The given parameters are;

The sum of the dimension of the cuboid = 9 cm

Required:

The value sum of the dimension of the edges the cuboid.

Solution:

The dimensions of a cuboid are; Length, l, width, w, and height, h

We get;

l + w + h = 9

The number of times that each dimension appear = 4 times

4 edges with the same length as the height, h

4 edges with the same length as the width, w

4 edges with the same length as the length, l

The sum of the edge lengths is therefore; Sum Edges = 4·l + 4·w + 4·h

Which gives;

Sum Edges = 4·l + 4·w + 4·h = 4 × (l + w + h) = 4 × 9 = 36

The sum of the edge lengths = 36 cm.

Learn more here:

brainly.com/question/12978944

5 0

2 years ago

Show that every triangle formed by the coordinate axes and a tangent line to y = 1/x ( for x > 0)

vfiekz [6]

Answer:

Step-by-step explanation:

given a point $(x_0,y_0)$ the equation of a line with slope m that passes through the given point is

$y-y_0 = m(x-x_0)$ or equivalently

$y = mx+(y_0-mx_0)$ .

Recall that a line of the form $y=mx+b$ , the y intercept is b and the x intercept is $\frac{-b}{m}$ .

So, in our case, the y intercept is $(y_0-mx_0)$ and the x intercept is $\frac{mx_0-y_0}{m}$ .

In our case, we know that the line is tangent to the graph of 1/x. So consider a point over the graph $(x_0,\frac{1}{x_0})$ . Which means that $y_0=\frac{1}{x_0}$

The slope of the tangent line is given by the derivative of the function evaluated at $x_0$ . Using the properties of derivatives, we get

$y' = \frac{-1}{x^2}$ . So evaluated at $x_0$ we get $m = \frac{-1}{x_0^2}$

Replacing the values in our previous findings we get that the y intercept is

$(y_0-mx_0) = (\frac{1}{x_0}-(\frac{-1}{x_0^2}x_0)) = \frac{2}{x_0}$

The x intercept is

$\frac{mx_0-y_0}{m} = \frac{\frac{-1}{x_0^2}x_0-\frac{1}{x_0}}{\frac{-1}{x_0^2}} = 2x_0$

The triangle in consideration has height $\frac{2}{x_0}$ and base $2x_0$ . So the area is

$\frac{1}{2}\frac{2}{x_0}\cdot 2x_0=2$

So regardless of the point we take on the graph, the area of the triangle is always 2.

6 0

3 years ago

Please help if you can

ArbitrLikvidat [17]

Answer:50

Step-by-step explanation:

All you do is add 60 and 70 together and then subtract what you had got from 180 witch gives you the answer for y and sense x is vertical to y they are going to be the same.

4 0

3 years ago

junaid delivers 150 newspaper in 3 hours on his route. what is the rate per hour at which he delivers

Lapatulllka [165]

150/3 = 50
50 per hour

7 0

2 years ago

The perimeter of a triangle is 27. Each side of the triangle has length 2x-3. What is the value of x?

Bezzdna [24]

Answer:

x=6

Step-by-step explanation:

To find the perimeter of the triangle you need to add up all the sides, so if all the sides are 2x-3 the equation will look like this;

2x-3+2x-3+2x-3=27

which when combining like terms will leave it to be;

6x-9=27

Than move all the factors besides x over to the right side;

6x-9+9=27+9

6x = 36

6x/6 = 36/6

x = 6

so your answer will be x=6

8 0

2 years ago