There are two ways to do this
Method 1:
Find (f-g)(x) first
(f-g)(x) = f(x) - g(x)
(f-g)(x) = (5x^2+3) - (-2x+4)
(f-g)(x) = 5x^2+3+2x-4
(f-g)(x) = 5x^2+2x-1
Then plug in x = -3
(f-g)(-3) = 5(-3)^2+2(-3)-1
(f-g)(-3) = 5(9)+2(-3)-1
(f-g)(-3) = 45-6-1
(f-g)(-3) = 39-1
(f-g)(-3) = 38
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Method 2:
Find f(-3)
f(x) = 5x^2+3
f(-3) = 5(-3)^2+3
f(-3) = 5(9)+3
f(-3) = 45+3
f(-3) = 48
Find g(-3)
g(x) = -2x+4
g(-3) = -2(-3)+4
g(-3) = 6+4
g(-3) = 10
Subtract the two results
(f-g)(-3) = f(-3) - g(-3)
(f-g)(-3) = 48 - 10
(f-g)(-3) = 38
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Whichever method you pick, the answer is: 38
Dang I’m dumb byeee use photo math it’s a app
Answer:
p-value = 0.0063
Step-by-step explanation:
PLEASE CHECK ATTACHMENT FOR COMPLETE SOLUTION AND STEP BY STEP EXPLANATION
Given:
A line passes through (1,-2) and is perpendicular to 
.
To find:
The equation of that line.
Solution:
We have, equation of perpendicular line.
Slope of this line is
Product of slope of two perpendicular lines is -1.
Now, slope of required line is 
and it passes through (1,-2). So, the equation of line is
where, m is slope.
Therefore, the equation of required line is .
