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3 years ago

11

What is the value of RT or x

1 answer:

Anna007 [38]3 years ago

7 0

Write and solve an equation of ratios:

x 9

---- = ----

16 x

Cross mult., we get x^2 = (16)(9)

Taking the sqrt of both sides, we get x = plus or minus (4)(3), or

x= plus or minus 12

Since x is measure of distance here, omit the -12 result. x = +12 units

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Find the smallest value of k when 280 is a perfect square

alexandr402 [8]

Answer:

i don't know do you play free fire

4 0

2 years ago

What is the directrix of the parabola defined by (x + 3)2 = -20(y − 1)?

Aleks [24]

We have that

(x + 3)² = -20(y − 1)
<span>This is actually the vertex form, so we can obtain the vertex already
</span>the vertex is the point (h,k)------------> (-3,1)

4p=-20------------> p=-5
Focus is at (-3,1-5)---------> (-3,-4)
Directrix is at <span>y = 1-(-5)----------> y=6
</span>
the answer is
the directrix is y=6

see the attached figure

4 0

3 years ago

Jamie needs to build a fence around his garden, as illustrated by polygon ABCDEF on the coordinate grid below. If each unit repr

NNADVOKAT [17]

Answer:

C. 26 yards

Step-by-step explanation:

Jamie's fence total length = perimeter of the polygon

Perimeter of the polygon = AB + BC + CD + DE + EF + FA

AB, FA and DE can be worked accordingly as shown below:

AB = |-5 - 0| = 5 units

FA = |5 - 2| = 3 units

DE = |1 -(-2)| = 3 units

BC, CD, and EF can be calculated using the formula $d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

Distance between B(0, 5) and C(4, 2):

$BC = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

Let,

$B(0, 5) = (x_1, y_1)$

$C(4, 2) = (x_2, y_2)$

$BC = \sqrt{(4 - 0)^2 + (2 - 5)^2}$

$BC = \sqrt{(4)^2 + (-3)^2}$

$BC = \sqrt{16 + 9} = \sqrt{25}$

$BC = 5 units$

Distance between C(4, 2) and D(1, -2)

$CD = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

Let,

$C(4, 2) = (x_1, y_1)$

$D(1, -2) = (x_2, y_2)$

$CD = \sqrt{(1 - 4)^2 + (-2 - 2)^2}$

$CD = \sqrt{(-3)^2 + (-4)^2}$

$CD = \sqrt{9 + 16} = \sqrt{25}$

$CD = 5 units$

Distance between E(-2, -2) and F(-5, 2):

$EF = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

Let,

$E(-2, -2) = (x_1, y_1)$

$F(-5, 2) = (x_2, y_2)$

$EF = \sqrt{(-5 -(-2))^2 + (2 -(-2))^2}$

$EF = \sqrt{(-3)^2 + (4)^2}$

$EF = \sqrt{9 + 16} = \sqrt{25}$

$EF = 5 units$

Total length of the wall in yards = 5 + 5 + 5 + 3 + 5 + 3 = 26 yards

4 0

3 years ago

What is the slope-intercept equation (y = mx + b) of the line that goes through the points

White raven [17]

The slope is m=3
hope this helps

4 0

3 years ago

If there are 6 hours in a school day, 5 school days in a week, 4 school weeks in a

Vanyuwa [196]

Answer:

1080hrs

Step-by-step explanation:

$\frac{6hr}{1day} \times5 \frac{days}{week}$

days cancel, redefine week as =5days

$\frac{30hr}{1week} \times 4 \frac{weeks}{month}$

weeks cancel redefine 4 weeks = 1 month

$\frac{120hr}{1month} \times 9 \frac{month}{1year}$

months cancel, redefine 9months= 1years

$\frac{120 \times 9}{1year}$

1080hrs per year (if I mathed 120x9 correctly that is, I didn't use a calculator so please double check that 120x9=1080)

7 0

3 years ago

Read 2 more answers