Find the 11th term of the following geometric sequence. 2, 8, 32, 128, ...

1 answer:

4 0

The 11th term is 2, 095, 152

Explanation:
This is a geometric sequence, since each term after the first is obtained by multiplying a common ratio,
r
.
The common ratio is
4
. The first term,
a
, is
2
. The number of terms,
n
is
11
.
We use the formula
t
n
=
a
×
r
n
−
1
to determine the nth term in a geometric sequence.
t
11
=
2
×
4
11
−
1
t
11
=
2
,
095
,
152
Hopefully this helps!

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