Find the mode of the set data: 49, 41, 46, 28, 33, 47, 29, 27, 47, 52, 32.

URGENT PLEASE HELP ME!!

Andrews [41]

Answer:

D 2400 ft^2

Step-by-step explanation:

His joumey maps out a right angles triangle with base 80 and height 60.

The required area = 1/2 * 80 * 60

= 2400 ft^2

4 0

3 years ago

PLEASE HELP!!!! 100 ÷ 25 • 20 + 4 ÷ 2 – 14

Zolol [24]

The answer is 38

Hope this helps : )

3 0

3 years ago

Read 2 more answers

A quality control expert at LIFE batteries wants to test their new batteries. The design engineer claims they have a variance of

iris [78.8K]

Answer:

The probability that the mean battery life would be greater than 533.2 minutes (in a sample of 75 batteries) is $\\ P(z>0.48) = P(x>533.2) = 0.3156$

Step-by-step explanation:

The main thing we have to take into account in this question is that we are about to find the probability of a sample mean. The distribution for sample means follows a normal distribution with mean $\\ \mu$ and standard deviation $\\ \frac{\sigma}{\sqrt{n}}$ . Mathematically

$\\ \overline{x} \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

For values of the sample $\\ n \ge 30$ , no matter the distribution the data come from.

And the variable z follows a standard normal distribution, and, as we can remember, this distribution has a mean = 0 and a standard deviation = 1. Mathematically

$\\ z = \frac{\overline{x} - \mu}{\frac{\sigma}{\sqrt{n}}}$ [1]

That is

$\\ z \sim N(0, 1)$

We have a variance of 3364. That is, a standard deviation of

$\\ \sigma^2 = 3364; \sigma = \sqrt{3364} = 58$

The population mean is

$\\ \mu = 530$

The sample size is $\\ n = 75$

The sample mean is $\\ \overline{x} = 533.2$

With all this information, we can solve the question

The probability that the mean battery life would be greater than 533.2 minutes

Using equation [1]

$\\ z = \frac{\overline{x} - \mu}{\frac{\sigma}{\sqrt{n}}}$

$\\ z = \frac{533.2 - 530}{\frac{58}{\sqrt{75}}}$

$\\ z = \frac{3.2}{\frac{58}{8.66025}}$

$\\ z = \frac{3.2}{6.69726}$

$\\ z = 0.47780$

With this value of z we can consult a cumulative standard normal table (or use some statistic program) to find the cumulative probability for z (and remember that this variable follows a standard normal distribution).

Most standard normal tables have values for z for only two decimals, so we can round the previous value for z as z = 0.48.

Then

$\\ P(z$

However, in the question we are asked for $\\ P(z>0.48) = P(x>533.2)$ . As well as all normal distributions, the standard normal distribution is symmetrical around the mean, and we have

$\\ P(z>0.48) = 1 - P(z$

Thus

$\\ P(z>0.48) = 1 - 0.68439$

$\\ P(z>0.48) = 0.31561$

Rounding to four decimal places, we have

$\\ P(z>0.48) = 0.3156$

So, the probability that the mean battery life would be greater than 533.2 minutes is (in a sample of 75 batteries) $\\ P(z>0.48) = P(x>533.2) = 0.3156$ .

5 0

3 years ago

Two fifth grade classes are attending an amusement park as a field trip. Their teachers purchased the tickets for the class and

Tanya [424]

Answer:

1 Adult ticket=$35

1 Children ticket=$20

Step-by-step explanation:

21C+15A=945

6C+6A=330

we find adult tickets 1st

42C+30A=1890

42C+42A=2310

12A=420

A=35

we will find children ticket next

42c+30a=1890

30c+30a=1650

12c=240

C=20

3 0

3 years ago

A jet flew to the maintenance facility and back. The trip there took ten hours and the trip back took four hours. It averaged 42

Lana71 [14]

Speed is distance over time

miles per hour is distance over time

so if it averaged 420 miles an hour

is it not 420 miles per hour?

perhaps i am misunderstanding something?

3 0

3 years ago