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loris [4]
3 years ago
7

Four less than the product of one and a number X. Please help me.

Mathematics
1 answer:
satela [25.4K]3 years ago
3 0

Answer:

x−4

Step-by-step explanation:

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The area (in square feet) of the school sign can be represented by
yawa3891 [41]

Answer:

5x^2+2x-432

Step-by-step explanation:

15x^2+x-215×2+x−2

=15x^2+x-430+x−2

=15x^2+x+x-430-2

=15x^2+2x-432

3 0
2 years ago
A sample of 15 data is as follows: 17, 18, 17, 17, 13, 18, 5, 5, 6, 7, 8, 9, 20, 17, 3. The mode of the data isa)4b)13c)17d)20Co
Degger [83]

The mode of the data of sample with 15 values is c) 17.

The mode of any sample of data can be calculated by finding the number that is present highest number of times. Based on this, we will look for the numbers that are present multiple times in the mentioned sample.

17, 18 and 5 are the three numbers that are present more than once. Now, let's see what is the frequency of each of these numbers.

Frequency of 17 - 4

Frequency of 18 - 2

Frequency of 5 - 2

Thus, the number 17 is present maximum number of times and hence is the mode of the data.

Learn more about mode -

brainly.com/question/14532771

#SPJ4

5 0
1 year ago
Find the value of k such the -2/3 is the zero of the function f(x)=4x+k/7
Mashutka [201]
f(x)=4x+k/7\\
f(- \frac{2}{3} )=- \frac{8}{3} +k/7=0\quad\Rightarrow\quad k= \frac{56}{3}
3 0
3 years ago
Simplify $\frac{-10a^2b^4}{5a^{-9}b^{-5}}$
r-ruslan [8.4K]
\bf ~~~~~~~~~~~~\textit{negative exponents}
\\\\
a^{-n} \implies \cfrac{1}{a^n}
\qquad \qquad
\cfrac{1}{a^n}\implies a^{-n}
\qquad \qquad 
a^n\implies \cfrac{1}{a^{-n}}
\\\\
-------------------------------\\\\
\cfrac{-10a^2b^4}{5a^{-9}b^{-5}}\implies \cfrac{-10}{5}\cdot \cfrac{a^2b^4}{a^{-9}b^{-5}}\implies \cfrac{-2}{1}\cdot \cfrac{a^2a^9b^4b^5}{1}
\\\\\\
-2a^{2+9}b^{4+5}\implies -2a^{11}b^9
5 0
3 years ago
How many zeros are at the end of the number ^
Ymorist [56]

Answer:

7 zeros

Step-by-step explanation:

2¹² = 4096

5⁷ = 78,125

4096 × 78125 = 320,000,000

The number has seven zeros at the end of it.

Hope that helps.

8 0
3 years ago
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