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Sphinxa [80]
3 years ago
12

Factor 8x^2-24 by taking out the gcf

Mathematics
1 answer:
Ghella [55]3 years ago
5 0
<h3>Answer:    8(x^2-3)</h3>

Since 24 = 8*3, we can factor out the GCF 8 like so

8x^2 - 24 = 8*x^2 - 8*3 = 8(x^2-3)

This is using the distributive property.

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What is the period of the graph of y = 5cos(6x – 1) + 3?<br> O A.
evablogger [386]

Step-by-step explanation:

The coefficent of the x variable is b.

The formula for the period is

\frac{2\pi}{ |b| }

Here, b is 6 so we have

\frac{2\pi}{ |6| }  =  \frac{\pi}{3}

So the period is pi/3, or 60 degrees

5 0
2 years ago
The ages of the members of a family are 65, 58, 27, 25, 5, and 2 years old. What is the total admission price for the family to
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2 years ago
What is the Greatest Common Factor of x4 and x3? (1 point)
denis-greek [22]
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4 0
4 years ago
Read 2 more answers
Lizette is training for a marathon. At 7:00 she left her house and ran until 8:30, then she walked until 11:30. She covered a to
Leokris [45]
<h3>Answer:</h3>
  • running speed: 8 mph
  • walking speed: 2 mph
<h3>Step-by-step explanation:</h3>

Let w represent Lizette's walking speed. Then her running speed is w+6. The relationship between speed, time, and distance is ...

  distance = speed × time

Lizette ran for 1.5 hours, then walked for 3 hours. Her total distance is ...

  (w+6)·1.5 + w·3 = 18

  4.5w + 9 = 18 . . . . . simplify

  4.5w = 9 . . . . . . . . . subtract 9

  w = 2 . . . . . . . . . . . .divide by 4.5

Lizette's walking speed is 2 mph; her running speed is 8 mph.

6 0
3 years ago
Read 2 more answers
PLEASE HELP I DON'T UNDERSTAND
OLga [1]
X = the number of months the tire was used
y = the thickness of the tire tread

y = -(3/7)x + 20

Substitute x for 20 (the number of months the tire was used) and solve for y.

The next question: Substitute x for 49 (the number of months the tire was used) and solve for y.


6 0
3 years ago
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