Question

Energy that is not utilized for work or heat transfer is converted to the chemical energy of body fat containing about 39 kJ/g. How many grams of fat will you gain if you eat 10,000 kJ (about 2390 kcal) one day and do nothing but sit relaxed for 14.3 h and sleep for the other 9.70 h

Answer 1

Answer:

$m=107.8g$

Explanation:

Hello,

In this case, for the given information, we can compute the gained grams by firstly compute the energy consumed by 14.3 h of being sit relaxed and 9.70 h  of sleeping:

$E_{sit}=120\frac{J}{s}*\frac{3600s}{1h} *14.3h*\frac{1kJ}{1000J} =6177.6kJ\\\\E_{sleep}=83\frac{J}{s}*\frac{3600s}{1h} *9.70h*\frac{1kJ}{1000J} =2898.36kJ$

Then, we compute the energy used that day:

$E_T=10000kJ-2898.36kJ-6177.6kJ=4203.28kJ$

Finally, the mass by considering the consumed fat:

$m=\frac{4203.28kJ}{39kJ/g} \\\\m=107.8g$

Regards.