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laiz [17]
3 years ago
8

A chemist working as a safety inspector finds an unmarked bottle in a lab cabinet. A note on the door of the cabinet says the ca

binet is used to store bottles of carbon tetrachloride, diethylamine, methyl acetate, ethanolamine, and dimethyl sulfoxide.
The chemist plans to try to identify the unknown liquid by measuring the density and comparing to known densities. First, from his collection of Material Safety Data Sheets (MSDS), the chemist finds the following information:

Liquid Density
Tetrahydrofuran 0.89·gcm^−3
Carbon tetrachloride 1.6·gcm^−3
Pentane 0.63·gcm^−3
Dimethyl sulfoxide 1.1·gcm^−3
Acetone 0.79·gcm^−3.

Next, the chemist measures the volume of the unknown liquid as 0.852L and the mass of the unknown liquid as 938.g . Calculate the density of the liquid.
Chemistry
1 answer:
BaLLatris [955]3 years ago
8 0

Answer: The density of the liquid is 1.10g/cm^3

Explanation:

Density is defined as the mass contained per unit volume.

Density=\frac{mass}{Volume}

Given : Mass of the unknown liquid  = 938 grams

Volume of the unknown liquid = 0.852L=852cm^3  (1L=1000cm^3

Putting in the values we get:

Density=\frac{938g}{852cm^3}

Density=1.10g/cm^3

Thus the density of the liquid is 1.10g/cm^3 and the liquid is dimethyl sulfoxide.

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Answer:

i hope this will help you :)

Explanation:

number of electrons=36

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mass number=78

so the element will be krypton Kr

as elements are identified on their number of electrons so this atom is krypton

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Calculate the molarity of glucose in a solution that which contains 35 g of glucose in 0.16 kg of phenol
sleet_krkn [62]
C(Molarity) = n of solute/V of solution (mol/L)

glucose(C6H12O6) = 180g/mol
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