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3 years ago

I can't find the value of nickels, dimes, and quarters

Mathematics

1 answer:

liberstina [14]3 years ago

6 0

There are 16 Quarters which equals $4.00 plus 16 nickels which equals $0.80 then there is 16 times three so there is 48 dimes which equals $4.80.
$4.00 plus $0.80 equals $4.80 plus $4.80 equals $9.60

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100 x 54 + 77 ÷ 2 = ? (RIGHT ANSWER GETS BRAINLIEST)

Nadusha1986 [10]

Answer:

5438.5

Step-by-step explanation:

To complete this equation, we must use the order of operations also known as PEMDAS.

For the case of this problem, we start by multiplying or dividing numbers before adding or subtracting numbers.

First let's start on the left:

100 x 54 + 77 ÷ 2

5,400 + 77 ÷ 2

5,400 + 38.5

5438.5

I hope this helps! Just remember to always add or subtract number last and start on the left, so that you don't get confused.

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3 years ago

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lisov135 [29]

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10. Which one of the following pairs of numbers contains like fractions?

tangare [24]

Answer:

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2 years ago

the length of a sandbox is three feet longer than it’s width. Write the expression that would represent the area of the sandbox.

Rashid [163]

Part A : D.)

Part B : Length of the sandbox is 10 feet.

Step-by-step explanation:

Given,

Perimeter = 29 ft

We need to find the equation for the perimeter and also the length of the sandbox.

Solution,

Let the width of the sandbox be 'w'.

Now as per question said;

The length of the sandbox is 1 foot longer than twice the width of the sandbox.

So we can say that;

Length =

Now we know that the perimeter is equal to the sum of twice of length and width.

framing in equation form, we get;

Perimeter =

we have given the perimeter, so on substituting the value, we get;

Hence The equation used to find the width is .

Now we solve for 'w'.

Applying distributive property, we get;

Subtracting both side by '2' we get

Dividing both side by 6 we get;

Width of the sandbox = 4.5 ft

Length of the sandbox =

Hence Length of the sandbox is 10 feet.

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3 years ago

A cube-shaped box has a volume of 1/8 of a cubic meter. What is the perimeter of each of its

belka [17]

Given:

The volume of a cube-shaped box is $\dfrac{1}{8}$ cubic meter.

To find:

The perimeter of each of its faces.

Solution:

Let "a" be the side length of the cube shaped box. Then the volume of the box is:

$V=(side)^3$

$V=a^3$

It is given that the volume of a cube-shaped box is $\dfrac{1}{8}$ cubic meter.

$a^3=\dfrac{1}{8}$

Taking cube root on both sides, we get

$a=\dfrac{1}{2}$

Now, the perimeter of each face of a cube is:

$P=4a$

Where, a is the side length of the cube.

Putting $a=\dfrac{1}{2}$ , we get

$P=4\times \dfrac{1}{2}$

$P=2$

Therefore, the perimeter of each face of a cube-shaped box is 2 meters.

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3 years ago