Answer:
First, plug-in x and y as 3sinθ-2 and 3cosθ+4 into the equation, respectively:
Then, +2 and -2 cancel out and +4 and -4 cancel out as well, leaving you with:
We can factor out 3^2 = 9 from both equations:
We know from a trigonometric identity that , meaning we can reduce the equation to:
And therefore, we have shown that (x+2)^2 + (y-4)^2 = 9, if x=3sinθ-2 and y=3cosθ+4.
Hope this helped you.
Answer:
Step-by-step explanation:
We have been given a function . We are asked to find the zeros of our given function.
To find the zeros of our given function, we will equate our given function by 0 as shown below:
Now, we will factor our equation. We can see that all terms of our equation a common factor that is .
Upon factoring out , we will get:
Now, we will split the middle term of our equation into parts, whose sum is and whose product is
. We know such two numbers are
.
Now, we will use zero product property to find the zeros of our given function.
Therefore, the zeros of our given function are .