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rodikova [14]
3 years ago
10

Two angles are given m m

Mathematics
1 answer:
Paul [167]3 years ago
6 0

which means that:

m+m= Something.

and that something can be anything,it determines on the m+m to find out what the answer might be.

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The equation 2y+x0 is shown on the graph below as a:
kirza4 [7]
I think it’s the red line.
So you want to put the equation into y=mx+b so you would need to subtract the x to put it on the right side so then you’ll have 2y=-x+0 then divide by 2 to get the y by itself then you’ll have y=-2x+0 that means the line would be negative and the y intercept is 0 and the only line that follows that is the red line.

Hope this helped :)
3 0
2 years ago
What is the solution of the equation 3^5 sqrt (x+2)^3+3=27?
BlackZzzverrR [31]
3^5) (x + 2)^(3/2) + 3 = 27 
<span>(x + 2)^(3/2) = 24 / 243 </span>
<span>x + 2 = [ 24 / 243 ]^(2/3) </span>
<span>x + 2 = [ 8 / 81 ]^(2/3) </span>
<span>x = [ 4 / 81^(2/3) ] - 2 =-1.786

the answer is x=-1.786</span>
4 0
3 years ago
Read 2 more answers
Write an equasion of the line in point-slope form that passes through the points (-16, 8) (4,2)
xeze [42]
You start by finding the slope :  y2 - y1 / x2 - x1

                                                 2 - 8 /  4 - (-16)
                                                   
                                                  - 6 / 20
                      
                                           m =  - 3 / 10 

Point slope form :  y - y1 = m( x- x1 )

           You can pick either of the coordinates and substitute them in

 POINT SLOPE FORM EQUATION   : y - 8 = -3/10 ( x + 16 )

5 0
2 years ago
Help would be very needed
Ipatiy [6.2K]

Answer:

Step-by-step explanati

28 cm2

4 0
3 years ago
Given right triangle ABCABC with altitude \overline{BD}
Alex

Answer:

x = 2\sqrt{11}

Step-by-step explanation:

AD = 4

AC = 11

DC = 11 - 4 = 7

First, find BD using the right triangle altitude theorem:

BD = \sqrt{AD*DC}

Plug in the values

BD = \sqrt{4*7}

BD = 2\sqrt{7}

Use pythagorean theorem to find x:

x² = AD² + BD²

Plug in the values

x^2 = 4^2 + (2\sqrt{7})^2

x^2 = 4^2 + (2\sqrt{7})^2

x^2 = 16 + (4*7)

x^2 = 16 + 28

x^2 = 44

Take the square root of both sides

\sqrt{x^2} = \sqrt{44}

x = \sqrt{44}

x = \sqrt{4 * 11}

x = 2\sqrt{11}

6 0
3 years ago
Read 2 more answers
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