Answer:
The company's profit be in the year 2008 is $8.3 million.
Step-by-step explanation:
Given:
In the year 2006, a company made $7 million in profit, their profit increased by 9%.
So, we need to calculate the company's profit be in the year 2008.
Now, by putting the formula to find the profit(P) after the two year:
Difference between the year = 2008 - 2006 = 2 year.
So, <u><em>number of years(n) = 2 year</em></u>
<u><em>Rate of profit increasing(r) = 9%</em></u>
<u><em>Amount company made in 2006 (A) = $7 million</em></u><u>.</u>






<em>Profit in the year 2008 would be 8.316 million, and nearest to the tenth of a million dollars is $8.3 as 3 is in the tenth place of the decimal and 1 in the hundredth so rounding will change $8.316 to $8.3.</em>
Therefore, the company's profit be in the year 2008 is $8.3 million.