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kompoz [17]
3 years ago
12

Plssss Help!!! Will mark brainiest!!

Mathematics
1 answer:
marshall27 [118]3 years ago
5 0

Answer:

the last one

Step-by-step explanation:

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What is the value of sin C? <br><br> A) 8/15<br> B)8/17<br> C)15/8<br> D)15/17
arlik [135]

sin is the opposite side over the hypotenuse so

sin C is 8/ 17 or B

7 0
3 years ago
What is the mean and mad of this data set?
larisa86 [58]

Answer:

The mean number of gerbils seen per day is 6.

The mean absolute deviation of the data is 2.29.

Step-by-step explanation:

The mean of a data set is the value that represents the entire data set. It is the average value.

The formula to compute the mean of a data set is:

\bar x=\frac{1}{n}\sum X

The mean absolute deviation (MAD) of a data set is the average distance amid each value and the mean. The MAD provides us with an idea about the deviation in the data set.

The formula to calculate the value of MAD is:

MAD=\frac{1}{n}\sum |x-\bar x|

The data set for the number of gerbils seen per day is:

S = {2, 3, 5, 7, 8, 8, 9}

Compute the mean of the data as follows:

\bar x=\frac{1}{n}\sum X

  =\frac{1}{7}\times [2+3+5+7+8+8+9]\\\\=\frac{1}{7}\times 42\\\\=6

The mean number of gerbils seen per day is 6.

Compute the mean absolute deviation of the data as follows:

MAD=\frac{1}{n}\sum |x-\bar x|

          =\frac{1}{7}\times [|2-6|+|3-6|+|5-6|+|7-6|+|8-6|+|8-6|+|9-6|]\\\\=\frac{1}{7}\times 16\\\\=2.2857\\\\\approx 2.29

Thus, the mean absolute deviation of the data is 2.29.

5 0
4 years ago
Find the volume of the right cone. Shown as a decimal rounded to the nearest tenth 26 and 18
marysya [2.9K]

Answer:

caculate the area of a rectangle of length with 250cm and width with 200cm

5 0
3 years ago
BE || CD 1. Given 2. ∠A ≅ ∠A 2. Reflexive Property 3. ∠ACD ≅ ∠ABE 3. Corresponding angles formed by parallel lines and a transve
Ede4ka [16]

Answer:

The correct option is Segment Addition Postulate

Step-by-step explanation:

The segment addition postulate states that where there are two points on a line A and C and a third point B can only be located on the line segment AB if and only if the the distances between point A and point B as well as the distance between point B and point C satisfy the equation AB + BC = AC

Therefore, given that in the figure,  the point B is in between point A and point C on segment AC then AB + BC

Similarly, AD = AE + ED.

5 0
3 years ago
Hi everyone, I'm having trouble with this question and I'm not sure how to do it/where to start. Does anyone have a solution to
Andreyy89

This is quite an interesting problem. I am not sure how high you are in math, but I am going to use calculus I techniques to solve it. First, we need to model an equation. Let P be the total profit and x be every time you increase the cost by $10. If you think about it hard enough you come up with the equation

P(x)=(200-5x)(250+10x)

(200-5x) is the amount of plots you will be able to sell, and (250+10x) is the amount you charge for. So, at x =0

P(0)=(200-5(0))(250+10(0))=(200)(250)=$50,000

This is the initial condition where if we sell 200 plots at $250/plot.

So, this equation makes sense.

Now, let's maximize using the first derivative of the function.

Let's get it into an easily differentiable form.

P(x)=(200-5x)(250+10x)=-50x^2+2000x-1250x+50000\\=-50x^2+750x+50000

From here, differentiate the problem.

P'(x)=-100x+750

Now, set it equal to zero and solve for x.

P'(x)=-100x+750=0\\x=7.5

This a critical point of the function. Let's plug back into the original equation to see what it gives us.

P(7.5)=(200-5(7.5))(250+10(7.5))=(162.5)(325)=52,812.50

You cant sell half a plot, so we need to see what happens if we sell 162 plots and 163 plots, and then compare which one gives us more money.

In order to sell 162 plots

200-5x=162\\x=7.6Plug back into P(x) to see the profit

P(7.6)=(200-5(7.6))(250+10(7.6))=(162)(326)=52,812

Now, do the same for 163 plots

200-5x=163\\x=7.4\\P(7.4)=(200-5(7.4))(250+10(7.4))=(163)(324)=52,812

As we can see, they are the same. So, you can charge either $324 or $326 in rent. But, if your teacher is not looking for a logical answer and you can somehow sell half a plot, you can charge $325 in rent for the maximum profit.

6 0
3 years ago
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