Question

What is the second term of (s+v)^5a)25s^4b)25s^4vc)5s^4vd)125s^4v

Answer 1

By pascal triangle this second term should be
5s^4v<span />

Answer 2

ANSWER

$T_2 = 5s^{4}v$



EXPLANATION


We can use the binomial theorem for a specified term to find the second term.



This is given by,

$T_{r+1}=^nC_ra^{n-r}b^r$

For the second term,

$r + 1 = 2$


This implies that,


$r = 1$
By comparing


$(s+v)^5$

to

$(a+b)^n$

$a = s$
$b = v$

and

$n = 5$

We substitute all these into the formula to get,


$T_2=^5C_1s^{5-1}v^1$

$T_2=^5C_1s^{4}v$



$T_2 = 5s^{4}v$


The correct answer is C