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1 year ago

S is a subset within a universal set, U

1 answer:

nataly862011 [7]1 year ago

4 0

Keys on a keyboard because it can’t be letters because there are numbers and punctuation marks, it can’t be numbers because there are letters and punctuation marks, it can’t be punctuation merks either cause there are letters and numbers. So the only option left is keys on a keyboard cause it has all letters numbers and punctuation marks

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If a/b < c/d with b > 0, d > 0, prove that a+c / b+d lies between the two fractions a/b and c/d .

Tems11 [23]

Divide through everything by b :

$\dfrac{a+c}{b+d} = \dfrac{\dfrac ab + \dfrac cb}{1 + \dfrac db}$

Since a/b < c/d, it follows that

$\dfrac{a+c}{b+d} < \dfrac{\dfrac cd+\dfrac cb}{1 + \dfrac db}$

Multiply through everything on the right side by b/d to get

$\dfrac{a+c}{b+d} < \dfrac{\dfrac{bc}{d^2}+\dfrac cd}{\dfrac bd+1} = \dfrac{\dfrac cd\left(\dfrac bd+1\right)}{\dfrac bd+1} = \dfrac cd$

and so (a + c)/(b + d) < c/d.

For the other side, you can do something similar and divide through everything by d :

$\dfrac{a+c}{b+d} = \dfrac{\dfrac ad + \dfrac cd}{\dfrac bd + 1}$

and a/b < c/d tells us that

$\dfrac{a+c}{b+d} > \dfrac{\dfrac ad + \dfrac ab}{\dfrac bd + 1}$

Then

$\dfrac{a+c}{b+d} > \dfrac{\dfrac ab + \dfrac{ad}{b^2}}{1 + \dfrac db} = \dfrac{\dfrac ab\left(1+\dfrac db\right)}{1 + \dfrac db} = \dfrac ab$

and so (a + c)/(b + d) > a/b.

Then together we get the desired inequality.

5 0

3 years ago

Geometry help please!

Gekata [30.6K]

given the following sets.

A = {0, 1, 2, 3}
B = {a, b, c, d}
C = {0, a, 2, b}

Find B C.

3 0

3 years ago

Use the graph below to choose the correct statements. Select all that apply

kati45 [8]

Is there any duplicate in x-value wrt y-value if you apply the vertical line test?

3 0

3 years ago

Cindy multiple her age by 5, subtracted 12, and then divide by 3. The result was 16. How old is Cindy?

sergejj [24]

Let's give Cindy's age a variable.

Cindy's age = x

Cindy multiplies her age by 5

x(5)

Subtracted by 12

x(5) - 12

Divide by 3

(5x - 12)/3

The result was 16

(5x - 12)/3 = 16

Let's solve

Multiply both sides by 3

(5x - 12) = 48

Open brackets

5x - 12 = 48

Add 12 to both sides

5x = 60

Divide by 5 on both sides to isolate x

x = 12

Cindy is 12 years old.

8 0

2 years ago

Please help me out! It’s urgent!

LuckyWell [14K]

Answer:

8 square units

Step-by-step explanation:

Area of the shaded shape = sum of shaded squares × 1 square unit

= 8 × 1 = 8 square units

6 0

2 years ago