Use the second list of random numbers to again calculate the experimental probability of a group having at least three
1 answer:
You might be interested in
Order of operations are:
<span>1. Parentheses (simplify inside 'em)
2. Exponents
3. Multiplication and Division (from left to right)
<span>4. Addition and Subtraction (from left to right)
So, on your first one:
Parentheses first:
8(3+4)-2*8/(5-3)
8(7)-2*8/(2)
There are no exponents so multiplication and division:
56-16/2
56-8
Finally, addition and subtraction:
56-8=48
Your second problem is a bit more complicated but follows the same rules:
</span></span>
<span><span>
Parentheses first:
</span></span>
<span><span>
Now, exponents. Even though they are inside parentheses, we can't go further until we simply those.
(64+81)/5
Now back to parentheses:
(145)/5
Division:
145/5=29
Hope that helps</span></span>
<span>1. Parentheses (simplify inside 'em)
2. Exponents
3. Multiplication and Division (from left to right)
<span>4. Addition and Subtraction (from left to right)
So, on your first one:
Parentheses first:
8(3+4)-2*8/(5-3)
8(7)-2*8/(2)
There are no exponents so multiplication and division:
56-16/2
56-8
Finally, addition and subtraction:
56-8=48
Your second problem is a bit more complicated but follows the same rules:
</span></span>
<span><span>
Parentheses first:
</span></span>
<span><span>
Now, exponents. Even though they are inside parentheses, we can't go further until we simply those.
(64+81)/5
Now back to parentheses:
(145)/5
Division:
145/5=29
Hope that helps</span></span>