Answer:
0.50 kg of the material would be left after 10 days.
0.25 kg of the material would be left after 20 days.
Step-by-step explanation:
We have been given that the half-life of a material is 10 days. You have one 1 kg of the material today. We are asked to find the amount of material left after 10 days and 20 days, respectively.
We will use half life formula.
, where,
A = Amount left after t units of time,
a = Initial amount,
t = Time,
h = Half-life.
Therefore, amount of the material left after 10 days would be 0.5 kg.
Therefore, amount of the material left after 20 days would be 0.25 kg.
Answer:
a) x > − 24 
b) x < − 3
c) q < 56
Step-by-step explanation:
a) −2/5x−9<9/10
<=> 2/5x + 9 > − 9/10
<=> 2/5x > − 9/10 − 9
<=> 2×2/2×5x > − 9/10 − 9×10/10
<=> 4/10x > − 99/10
<=> x > − 99/4
<=> x > − 24
b) 4x+6<−6
<=> 4x < − 6 − 6
<=> 4x < − 12
<=> x < − 12/4
<=> x < − 3
c) q+12−2(q−22)>0
<=> q+12−2q −2×(−22)>0
<=> (q−2q) + (12+ 44) >0
<=> −q + 56 >0
<=> q < 56
The equation is 
.
1/2 is equivalent to 4/8, and 2 1/8 is equal to 17/8. (two full sets of 8 + 1 = 8 + 8 + 1, or 17)
The new equation is 
. Subtract the numerators.
17 - 4 = 13 or 13/8
The improper fraction 
simplifies to 
.
<h2>Answer:</h2>
Hope this helps :)
Answer:
3^4 / 8^2 or 81/64
Step-by-step explanation:
(-8)^-2 / 3^-4 =
= 3^4 / (-8)^2
= 3^4 / 8^2
= 81/64
The average of 45 and 19 is
32.
