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2 years ago

The binomial 5x – 4 is a factor of 10x2 – 23x + 12. What is the other factor?

1 answer:

6 0

$Method\ 1^o\\10x^2-23x+12=(5x-4)(ax+b)\\\\10x^2-23x+12=5ax^2+5bx-4ax-4b\\\\10x^2-23x+12=5ax^2+(5b-4a)x-4b\\\\therefore\\\\ \begin{array}{ccc}(1)\\(2)\\(3)\end{array}\left\{\begin{array}{ccc}5a=10\\5b-4a=-23\\-4b=12\end{array}\right\\\\(1)\ divide\ both\ sides\ by\ 5\to a=2\\(3)\ divide\ both\ sides\ by\ (-4)\to b=-3\\check\\subtitute\ the\ values\ of\ "a"\ and\ "b"\ to\ (2):\\5\cdot(-3)-4\cdot2=-15-8=-23\ /correct/\\\\Answer:\boxed{2x-3}$

$Method\ 2^o\\10x^2-23x+12=10x^2-8x-15x+12\\=2x\cdot5x-2x\cdot4-3\cdot5x-3\cdot(-4)\\=2x(5x-4)-3(5x-4)=(5x-4)\boxed{(2x-3)}$

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2 years ago

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Step-by-step explanation:

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2 years ago

Read 2 more answers

1. Determine a rule that could be used to explain how the volume of a

Eva8 [605]

Answer:

See explanation

Step-by-step explanation:

Solution:-

- We will use the basic formulas for calculating the volumes of two solid bodies.

- The volume of a cylinder ( V_l ) is represented by:

$V_c = \pi *r^2*h$

- Similarly, the volume of cone ( V_c ) is represented by:

$V_c = \frac{1}{3}*\pi *r^2 * h$

Where,

r : The radius of cylinder / radius of circular base of the cone

h : The height of the cylinder / cone

- We will investigate the correlation between the volume of each of the two bodies wit the radius ( r ). We will assume that the height of cylinder/cone as a constant.

- We will represent a proportionality of Volume ( V ) with respect to ( r ):

$V = C*r^2$

Where,

C: The constant of proportionality

- Hence the proportional relation is expressed as:

V∝ r^2

- The volume ( V ) is proportional to the square of the radius. Now we will see the effect of multiplying the radius ( r ) with a positive number ( a ) on the volume of either of the two bodies:

$V = C*(a*r)^2\\\\V = C*a^2*r^2$

- Hence, we see a general rule frm above relation that multiplying the result by square of the multiple ( a^2 ) will give us the equivalent result as multiplying a multiple ( a ) with radius ( r ).

- Hence, the relations for each of the two bodies becomes:

$V = (\frac{1}{3} \pi *r^2*h)*a^2$

$V = ( \pi *r^2*h)*a^2$

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