Answer:
43
Step-by-step explanation:
Based on the pattern of the scatter plot, 43 seems to be the better option.
Answer:
0.29
Step-by-step explanation:
Given :
n : ___ 0 _____ 1 ____ 2 ____ 3 ____ 4
P(n) : 0.82___ 0.11 ___0.04 _0.02 ___0.01
The expected number of defect in a shipment can be obtained using the expected value formula :
Expected value, E(X) = Σx*p(x)
Σx*p(x) = (0*0.82) + (1*0.11) + (2*0.04) + (3*0.02) + (4*0.01)
E(X) = 0.29
Hence, the expected number of defect in shipment is 0.29
7(4(1/2))+3(5(1/3))+2(-3(1/2))=
7(4/2)+3(5/3)+2(-3/2)=
7(2)+15/3+-6/2=
14+5-3=
19-3=
16
First you would subtract x from both sides to move all the x's to one side
Then you would add 4 to both side to move all the non x's to one side
Lastly divide by negative 15 to have x by itself
9/-15 =-.6
So x as has root at x=-0.6
