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3 years ago

Find the missing side.

Mathematics

1 answer:

Gre4nikov [31]3 years ago

7 0

The answer is 14.3. You use the sin trig function because you are looking for the side opposite the angle and you are given the hypotenuse.
So, sin73=x/15, sin73*15=14.3

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What's the answer to 9-2x=35 using distributive property? Pls HELP!

kati45 [8]

35 is the correct answer choice

6 0

3 years ago

Eight toymakers each carved 25 blocks and 15 cars. How many toys did they carve in all?

taurus [48]

Answer: 320 toys

Step-by-step explanation:

We can use an expression to solve this question.

8 (25 + 15)

8 (40)

320

4 0

3 years ago

Suppose that the members of a student governance committee will be selected from the 40 members of the student senate. There are

Len [333]

Answer:

The total number of ways to form a student governance committee is 1,211,760.

Step-by-step explanation:

The students senate consists of a total of 40 students.

The students are either Sophomores or Juniors or Seniors.

The number of students in each of these categories are as follows:

Sophomores = 18

Juniors = 12

Seniors = 10

A governance committee have to be selected from the students senate.

The committee have to made up of 2 sophomores, 2 juniors and 3 seniors.

Combinations can be used to select 2 sophomores from 18, 2 juniors from 12 and 3 seniors from 10.

Combinations is a mathematical technique used to determine the number of ways to select k items from n distinct items.

The formula is:

${n\choose k}=\frac{n!}{k!(n-k)!}$

(1)

Compute the number of ways to select 2 sophomores from 18 as follows:

${n\choose k}=\frac{n!}{k!(n-k)!}$

${18\choose 2}=\frac{18!}{2!(18-2)!}=\frac{18\times 17\times 16!}{2\times 16!}=153$

Thus, there are 153 ways to select 2 sophomores from 18.

(2)

Compute the number of ways to select 2 juniors from 12 as follows:

${n\choose k}=\frac{n!}{k!(n-k)!}$

${12\choose 2}=\frac{12!}{2!(12-2)!}=\frac{12\times 11\times 10!}{2\times 10!}=66$

Thus, there are 66 ways to select 2 juniors from 12.

(3)

Compute the number of ways to select 3 seniors from 10 as follows:

${n\choose k}=\frac{n!}{k!(n-k)!}$

${10\choose 3}=\frac{10!}{3!(10-3)!}=\frac{10\times 9\times 8\times 7!}{2\times 3\times 7!}=120$

Thus, there are 120 ways to select 3 seniors from 10.

The total number of ways to form a student governance committee that must have 2 sophomores, 2 juniors and 3 seniors is:

Total number of ways = ${18\choose 2}\times {12\choose 2}\times {10\choose 3}$

$=153\times 66\times 120\\=1211760$

Thus, the total number of ways to form a student governance committee is 1,211,760.

7 0

3 years ago

Can anyone please help, ;_;

BlackZzzverrR [31]

It was hard to figure this put but I'll just a take an educated guess and say that the answer is 10%.

7 0

3 years ago

Tommy and Sam met up for lunch. When they were done, Tommy traveled 3 blocks east and Sam traveled 3 blocks west. How many block

Molodets [167]

Answer:

Tommy traveled 6 blocks away from Tommy.

Step-by-step explanation:

8 0

3 years ago