Question

A=2/b+3c ; solve for c

Answer 1

Answer:

$c=\frac{a}{3} +\frac{2}{3b}$

Step-by-step explanation:

$a=\frac{2}{b} +3c$

Solve for x, we need to get 'c' alone

To remove fraction 2/b , we need to subtract 2/b from both sides

$a-\frac{2}{b}=\frac{2}{b}-\frac{2}{b}+3c$

$a-\frac{2}{b}=3c$

Divide by 3 on both sides

$\frac{a}{3} +\frac{2}{3b}=c$

Answer 2

Answer:

It is straightforward.

Answer is c= a/3 - 2/3b