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3 years ago

14

Jamere went to the beach. The list below shows the numbers of seashells collected on the beach each day.

1 answer:

Nina [5.8K]3 years ago

6 0

hi!

Step-by-step explanation:

good for jamere but i have no clue what you need help in but i tried ...right?

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Edgar has taken out a $6,250 unsubsidized Stafford loan to fund his four-year undergraduate degree. The loan has a duration of 1

maw [93]

Answer:

the answer is B. 1,722.22

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2 years ago

Becky graduated with a master degree in Personal Financial Planning. After working two years in a small financial planning firm,

Veronika [31]

Answer:

Becky graduated with a master degree in Personal Financial Planning. After working two years in a small financial planning firm, Becky earns $60,000 annually and saves $10,000 a year. What is her average propensity to consume?a.16.7%b.25.5%c.75.7%d.83.3%e.95.5%14. Which of the following goals is stated in a way that is most useful for developing a financial plan?

Step-by-step explanation:

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3 years ago

What is the smallest multiple of 18 of the form 2A945B, where A and B are digits?

musickatia [10]

Answer:

$219456$

Step-by-step explanation:

It must end in $0,2,4,6,8$ (divisible by 2 rule) and the digits must sum to a multiple of 9(divisible by 9 rule).

The digit sum is $2+A+9+4+5+B=20+A+B$ .

We want to make $A$ as low as possible because it's a higher digit than $B$ .

If $A$ is as low as possible, we have that the sum is $20+0+7=27$ . Uh-oh. $B$ has to be even! So $A=0$ doesn't work.

If $A=1$ , we have that the sum is $20+1+6=27$ . Yay!

So, the answer is $\boxed{219456}$

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2 years ago

During February Kevin water his IVy every third day and water his Cactus every fifth day well Kevin water both plants together a

Ivanshal [37]

Kevin will water both of his plants on the 15th.

The lowest common multiple of 3 and 5 is 15. Therefore, he will water both then.

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3 years ago

Show all work to solve by factoring 3x^2 − x − 2 = 0.

shtirl [24]

Answer:

The solutions are x=1 and x=-2/3

Step-by-step explanation:

we have

$3x^{2}-x-2=0$

Group terms that contain the same variable, and move the constant to the opposite side of the equation

$3x^{2}-x=2$

Factor the leading coefficient

$3(x^{2}-(1/3)x)=2$

Complete the square. Remember to balance the equation by adding the same constants to each side

$3(x^{2}-(1/3)x+(1/36))=2+(1/12)$

$3(x^{2}-(1/3)x+(1/36))=25/12$

Rewrite as perfect squares

$3(x-(1/6))^{2}=25/12$

$(x-(1/6))^{2}=25/36$

square root both sides

$(x-(1/6))=(+/-)(5/6)$

$x=(1/6)(+/-)(5/6)$

$x=(1/6)(+)(5/6)=1$

$x=(1/6)(-)(5/6)=-2/3$

4 0

3 years ago