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stepladder [879]

2 years ago

10

Find the product-3(5) I need help

2 answers:

Marizza181 [45]2 years ago

7 0

Answer: -15

The question asks you to find the "product," which means the result of multiplying. Both the word "product" and the parentheses indicate that you have to multiply.

Since it's a negative (-) multiplied by a positive (+), your product will be negative (-).

So, -3(5) = -15.

Daniel [21]2 years ago

4 0

Answer:

-15

Step-by-step explanation:

() means to multiply

So, -3(5) = -3 x 5 = -15

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see the attached figure to better understand the problem

we know that

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and

the area of the triangle is equal to

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in this problem

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we know that

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$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

Step $1$

<u>Find the distance AB</u>

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Substitute the values in the formula

$d=\sqrt{(2-2)^{2}+(6+2)^{2}}$

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Step $2$

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$B(6, 2),C(0, 8)$

Substitute the values in the formula

$d=\sqrt{(8-2)^{2}+(0-6)^{2}}$

$d=\sqrt{(6)^{2}+(-6)^{2}}$

$dBC=6\sqrt{2}\ units$

Step $3$

<u>Find the distance AC</u>

$A(-2, 2),C(0, 8)$

Substitute the values in the formula

$d=\sqrt{(8-2)^{2}+(0+2)^{2}}$

$d=\sqrt{(6)^{2}+(2)^{2}}$

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Step $4$

<u>Find the distance DC</u>

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Substitute the values in the formula

$d=\sqrt{(8-2)^{2}+(0-0)^{2}}$

$d=\sqrt{(6)^{2}+(0)^{2}}$

$dDC=6\ units$

Step $5$

<u>Find the perimeter of the triangle</u>

$P=AB+BC+AC$

substitute the values

$P=8\ units+6\sqrt{2}\ units+2\sqrt{10}\ units$

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therefore

The perimeter of the triangle is equal to $22.81\ units$

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substitute the values

$A=\frac{1}{2}*8*6$

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