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LenaWriter [7]
3 years ago
5

20 POINTS !!! ONLY HELP IF UR 100% SURE !!!

Mathematics
2 answers:
Arte-miy333 [17]3 years ago
8 0
Your answer is C for sure I am!
Olegator [25]3 years ago
8 0

Answer:

Step-by-step explanation:

initial 48,000

50% Decrease

Minnimum 94500

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I need help with a chapter quiz
Lostsunrise [7]

Answer:

hjhjkjhhu

Step-by-step explanation:

7 0
2 years ago
Find the equation of plane that contains P(1,-1,2) and has the normal n=2i+3j+5k (please answer quickly )
mixas84 [53]

Answer:

2x + 3y + 5z = 9

Step-by-step explanation:

The normal defines all the planes perpendicular to that vector. To isolate to a single plane, just apply the known point.

ax + by + cz = d

2x + 3y + 5z = d

2(1) + 3(-1) + 5(2) = 9

8 0
3 years ago
What is the volume of the cone with radius 5 inches and height 9 inches to the nearest cubic inch
charle [14.2K]

Answer:

236 inches^3

Step-by-step explanation:

V=πr^2 h/3

pi5^2*3

25*pi3

75pi

=235.62

7 0
3 years ago
Read 2 more answers
When Alice spends the day with the babysitter, there is a 0.6 probability that she turns on the TV and watches a show. Her littl
lara [203]

Answer:

A. P("Both Alice and Betty watch TV") = 12/25

B. P("Betty watches TV") = 12/25

C. P("Only Alice watches TV") = 3/25

Step-by-step explanation:

A. Because what we are told, Betty need that Alice turn on the TV, so, we first need the probability that she watches TV:

P(Alice)=3/5 (0.6)

And we know that:

P(Betty)=4/5 (0.8)

If we want the probability of both things happening at the same time (If you use a tree diagram, those events will be in the same branch), we proceed multiply them:

P("Both Alice and Betty watch TV") = 3/5 * 4/5 = 12/25

And this is the answer

B. Considering that Betty needs Alice to turn on the TV, the probability of Betty watching TV is the same as if she is with Alice.

P("Betty watches TV") = P("Both Alice and Betty watch TV") = 12/25

C. We use the same process as part A, but with a little difference. We now multiply for the probability that Betty does not watch TV (Because they still be in the same branch).

P("Betty does not watch TV") = 1 - P("Betty")

P("Betty does not watch TV") = 1 - 4/5

P("Betty does not watch TV") = 1/5

And the answer for part C is:

P("Alice watches TV without Betty") = 3/5 * 1/5 = 3/25

5 0
3 years ago
The diagonals of a rhombus are perpendicular.
Ivahew [28]
The rhombus always has perpendicular diagonals.
3 0
3 years ago
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