Question

Which lines have slope -4/5 and contains point (0,1)?

Answer 1

ANSWER

The required line is BC


EXPLANATION

We want to find the line that passes through
$(0,1)$

and has slope
$m = - \frac{4}{5}$


Since the x-value of the given point is zero, the point

$(0,1)$

is the y-intercept.


From the above graph, the two lines that contains
$(0,1)$

are line CE and line BC.

Since, the slope

$m = - \frac{4}{5}$
is negative, line BC is the required line because it is sloping backwards.


We can confirm this by using the point,


$B(-5,5)$

and

$C(0,1)$


to find the slope and obtain


$m = \frac{5 - 1}{ - 5 - 0} = - \frac{4}{5}$