Imagine that we cut the cone in half with a vertical plane. In this plane we'd see points a, b and c. We need to find the measure of angle bca, and then double that angle, to obtain the answer to this problem.
Note that tan (angle bca) = opp / adj = 2 / 6, or 1/3, or 0.333...
Working backwards to find angle bca, we use the inverse tangent function:
arctan 0.3333.. = approx. 0.322 radians, or 18.435 degrees.
Doubling that gives us the measurement of the angle formed between the line segments: 2(18.435 deg) = 36.9 degrees, approximately.
To write this expression as a positive exponent we use this rule of exponents: xa=1x−a. 5−3=15−−3=153. Use this rule for exponents: xa=1x−a. 5−3=15−−3=153=1125.
For the top angles you would solve them by setting them equal to each other, so you would do 3x+5=17x-70. You can then add 70 to both sides, getting 3x+75=17x. You can then subtract 3x from both sides, getting 75=14x. You then divide both sides, getting 5 5/14 or around 5.36 as x. You can then add plug that into 3x+5, getting around 21.07. You can then make the equation R=180-21.07. You'd get 158.93.
Answer:
StartFraction negative 1 Over k cubed EndFraction
Step-by-step explanation:
3k / (k + 1) × (k²- 1) / 3k³
= 3k(k² - 1) / (k + 1)(3k³)
= 3k³ - 3k / 3k⁴ + 3k³
= -3k / 3k⁴
= -1/k³
StartFraction k + 1 Over k squared EndFraction
(k + 1) / k²
StartFraction k minus 1 Over k squared EndFraction
(k - 1)/k²
StartFraction negative 1 Over k cubed EndFraction
= -1/k³
StartFraction 1 Over k EndFraction
= 1/k
Answer: The expression that represents Meg's finishing time in June is "y - 10".
The problem started with Meg running in April. She had a time in April and we called it "y".
Now, Meg ran again in June. In June, she did 10 seconds faster. So it makes since that we need to subtract 10 from her April time, "y". Therefore, the expression is simply "y - 10".
