Answer:
I cannot not give the correct solution, need more context. How many children are there, how many adults are in the family? So I will explain in my explanation.
Step-by-step explanation:
If more context were given, for example:<em> 2 adults and 2 children.</em>
Then the bakers would have bought 2 adult tickets for ___ each
Then the bakers would have bought 3 children's tickets for ___ each
So using what we know we can create an equation:
<em>2A+3C=28</em>,<em> </em>
meaning 2 adult tickets plus 3 children's tickets costs a total of $28.
So we divide 28 by 5, which is the total amount of tickets.
28/5=5.6
So to figure the cost of children's tickets multiply the cost by amount.
3*$5.6=$16.8, C=16.8
To figure out the cost of the adults tickets multiple the cost by the amount.
2*$5.6=$11.2, A=11.2
a) the bakers would have bought <u>2</u> adult tickets for <u>5.6</u> each.
b) the bakers would have bought <u>3</u> children's tickets for <u>5.6</u> each.
Answer:
b
Step-by-step explanation:
every cantaloup costs $3 so they would pay x × $3
but they got a $2 coupon so you have to deduct that.
Answer:
ig i will
Step-by-step explanation:
Answer:
ΔNAS≅ΔSEN by SSA axiom of congruency.
Step-by-step explanation:
Consider ΔNAS and ΔSEN,
NS=SN(Common ie . Both are the same side)
SA=NE( Given in the question that SA≅ NE)
∠SNA=∠NSE( Due to corresponding angle property where SE ║ NA)
Therefore, ΔNAS ≅ΔSEN by SSA axiom of congruency.
∴ NA≅SA by congruent parts of congruent Δ. Hence, proved.
Step-by-step explanation:
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