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Alik [6]
3 years ago
10

Suppose that technological advancements stimulate $20 billion in additional investment spending. If the MPC = 0.6, how much will

the change in investment increase aggregate demand? Question 5 options: A) $12 billion B) $33.3 billion C) $20 billion D) $50 billion
Business
1 answer:
grin007 [14]3 years ago
5 0

Answer:

option (D) $50 billion.

Explanation:

Data provided in the question:

Additional investment spending = $20 billion

MPC = 0.6

Now,

Increase in aggregate demand = [1 ÷ (1 - mpc) ] × Investment

or

Increase in aggregate demand =  [1 ÷ (1 - 0.4) ] ×  $20 billion

or

Increase in aggregate demand = (1 ÷ 0.4) × $20 billion

or

Increase in aggregate demand = 2.5 × $20 billion

or

Increase in aggregate demand = $50 billion

Hence.

the correct answer is option (D) $50 billion.

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3
iris [78.8K]

None of the options shows an alternative Tina has, a real alternative would be a credit card and cash ($190)

In economics, an alternative is an element that replaces or substitutes another. For an element to be considered an alternative it needs:

  • To belong to the same category or have the same function.
  • To be possible for the user to replace the first element using the alternative.

Based on this, let's analyze each of the options:

  • Jacket and $100: These are not alternatives because Tina wants a jacket and this product cannot be replaced with money as money will not protect Tina from cold weather.

  • Shoes and a jacket: These are not alternatives because Tina wants the two products not only one.

  • Credit card and $100: These would be alternatives if the total cost was $100. However, using a credit card Tina can pay for both products but using $100 she can only pay for one of the products.

Therefore, the options do not present alternatives; but one valid alternative is a credit card and $190.

Learn more in

7 0
3 years ago
The team that is planning the annual company sales meeting has members in several offices. They need to have a conversation abou
White raven [17]

Answer:

C

Explanation:

The question is asking what method of communication will be used by a team having to plan for the annual sales meeting.

This can be achieved by having a conference call. A conference call will provide the necessary framework needed by the members of the committee to communicate their thoughts effectively to all other members of the group. With conference call, opinions of each member can easily be passed or related to the other group members instantly

6 0
3 years ago
Accounting Professionals Inc. experienced the following events in 2014, its first year of operation:1. Performed services for $2
Andrews [41]

Answer:

Explanation:

The accounting equation is presented below:

Particulars       Assets   =               Liabilities   =             Stockholders equity  

                        Cash     Supplies          Account payable              Retained earnings

1. Service

Performed       $20,000                                                                    $20,000

2. Supplies

Purchased                       $4,000             $4,000

3. Supplies

Used                              -$3,000                                                         -$3,000

Total               $20,000  $1,000              $4,000                               $17,000

6 0
3 years ago
when comparing a retail business to a service business, the financial statement that changes the most is the
Leona [35]

Answer:

The income statement.

7 0
2 years ago
Each machine must be run by one of 19 cross-trained workers who are each available 35 hours per week. The plant has 10 type 1 ma
Mrac [35]

Answer:

The Linear programming model is given as below

Profit Function: P=90X+120Y+150Z

Constraints:

2X+2Y+Z\leq 400

3X+4Y+6Z\leq 240

4X+6Y+5Z\leq 320

\dfrac{2X+2Y+Z}{40}\leq 10

\dfrac{3X+4Y+6Z}{40}\leq 6

\dfrac{4X+6Y+5Z}{40}\leq 8

\dfrac{2X+2Y+Z}{35}+\dfrac{3X+4Y+6Z}{35}+\dfrac{4X+6Y+5Z}{35}\leq 19

Explanation:

As the question is not complete, the complete question is found online and is attached herewith.

Let the number of product 1 to be produced is X, that of product 2 is Y and product 3 is Z

so  the maximizing function is the profit function which is given as

P=90X+120Y+150Z

Now as the number of hours in a week are 40 and there are a total of 10 type 1 machines so the total number of machine 1 hours are 40*10=400 hours

As from the given table product 1 uses 2 machine hours of machine 1, product 2 uses 2 machine hours of machine 1 and product 3 uses 1 hour of machine 1 so

2X+2Y+Z\leq 400

Now as the number of hours in a week are 40 and there are a total of 6 type 2 machines so the total number of machine 2 hours are 40*6=240 hours

As from the given table product 1 uses 3 machine hours of machine 2, product 2 uses 4 machine hours of machine 2 and product 3 uses 6 hour of machine 2 so

3X+4Y+6Z\leq 240

Now as the number of hours in a week are 40 and there are a total of 8 type 3 machines so the total number of machine 3 hours are 40*8=320 hours

As from the given table product 1 uses 4 machine hours of machine 3, product 2 uses 6 machine hours of machine 3 and product 3 uses 5 hour of machine 3 so

4X+6Y+5Z\leq 320

Now as the machine 1 is used as 2X+2Y+Z in a week and the week is of 40 hours so the number of machines to be used are given as

\dfrac{2X+2Y+Z}{40}\leq 10

Now as the machine 2 is used as 3X+4Y+6Z in a week and the week is of 40 hours so the number of machines to be used are given as

\dfrac{3X+4Y+6Z}{40}\leq 6

Now as the machine 3 is used as 4X+6Y+5Z in a week and the week is of 40 hours so the number of machines to be used are given as

\dfrac{4X+6Y+5Z}{40}\leq 8

Now the workers are available for 35 hours so the worker available at the machine 1 is given as

\dfrac{2X+2Y+Z}{35}

That of machine 2 is given as

\dfrac{3X+4Y+6Z}{35}

That of machine 3 is given as

\dfrac{4X+6Y+5Z}{35}

As the total number of workers is 19 so the constraint is given as

\dfrac{2X+2Y+Z}{35}+\dfrac{3X+4Y+6Z}{35}+\dfrac{4X+6Y+5Z}{35}\leq 19

So the Linear programming model is given as below

Profit Function: P=90X+120Y+150Z

Constraints:

2X+2Y+Z\leq 400

3X+4Y+6Z\leq 240

4X+6Y+5Z\leq 320

\dfrac{2X+2Y+Z}{40}\leq 10

\dfrac{3X+4Y+6Z}{40}\leq 6

\dfrac{4X+6Y+5Z}{40}\leq 8

\dfrac{2X+2Y+Z}{35}+\dfrac{3X+4Y+6Z}{35}+\dfrac{4X+6Y+5Z}{35}\leq 19

4 0
3 years ago
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