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Gekata [30.6K]
2 years ago
11

Write the expression in correct forma13n² -6n⁴ + 2n -5n³ + 3​

Mathematics
1 answer:
m_a_m_a [10]2 years ago
4 0

Answer:

-6n^4 -5n^3 +13n^2 +2n +3

organize the exponents from higher to lower.

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A lighthouse has a shadow that is 36 feet long. Zara is 4 feet tall, and she is standing next to the lighthouse. Zara has a shad
xxTIMURxx [149]

At a particular time, objects and their shadows are proportionate.

Therefore, in figure,

\frac{AB}{FD}= \frac{BC}{DE} --- (1)

where AB is the height of the lighthouse, BC, its shadow and FD is the height of Zara and DE is her shadow.

From the given information,

BC = 36 feet

FD = 4 feet and DE = 3 feet

(1) becomes

\frac{AB}{4}= \frac{36}{3}

\frac{AB}{4}= 12

AB = 48

Hence, the height of the lighthouse is 48 feet.


8 0
3 years ago
Read 2 more answers
In Hamilton County, Ohio the mean number of days needed to sell a home is days (Cincinnati Multiple Listing Service, April, 2012
Diano4ka-milaya [45]

Answer:

t=\frac{80-86}{\frac{20}{\sqrt{40}}}=-1.8974    

p_v =2*P(t_{39}

If we compare the p value with a significance level given \alpha=0.05 we see that p_v>\alpha so we can conclude that we FAIL to reject the null hypothesis, so there is not enough evidence to conclude that the mean for the data is significantly different from 86 days.    

Step-by-step explanation:

Assuming the following problem: "In Hamilton County, Ohio the mean number of days needed to sell a home is 86 days (Cincinnati Multiple Listing Service, April, 2012). Data for the sale 40 of homes in a nearby county showed a sample mean of 80 days with a sample standard deviation of 20 days. Conduct a hypotheses test to determine whether the mean number of days until a home is sold is different than the Hamilton county mean of 86 days in the nearby county. "

1) Data given and notation    

\bar X=80 represent the sample mean

s=20 represent the sample standard deviation

n=40 sample size    

\mu_o =86 represent the value that we want to test  

\alpha=0.05 represent the significance level for the hypothesis test.  

z would represent the statistic (variable of interest)    

p_v represent the p value for the test (variable of interest)

2) State the null and alternative hypotheses.    

We need to conduct a hypothesis in order to determine if the mean is different from 86, the system of hypothesis would be:    

Null hypothesis:\mu = 86    

Alternative hypothesis:\mu \neq 86    

We don't know the population deviation, so for this case we can use the t test to compare the actual mean to the reference value, and the statistic is given by:    

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}} (1)    

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

3) Calculate the statistic    

We can replace in formula (1) the info given like this:    

t=\frac{80-86}{\frac{20}{\sqrt{40}}}=-1.8974    

4) Calculate the P-value    

First we need to find the degrees of freedom given by:

df=n-1=40-1=39

Since is a two tailed test the p value would be:    

p_v =2*P(t_{39}

In Excel we can use the following formula to find the p value "=2*T.DIST(-1.8974,39,TRUE)"  

5) Conclusion    

If we compare the p value with a significance level given \alpha=0.05 we see that p_v>\alpha so we can conclude that we FAIL to reject the null hypothesis, so there is not enough evidence to conclude that the mean for the data is significantly different from 86 days.    

7 0
3 years ago
Find the first six terms of the sequence.<br> a1 = -7, an = 4 • an-1
Juli2301 [7.4K]

Answer:

- 7, - 28, - 112, - 448, - 1792, - 7168

Step-by-step explanation:

Using the recursive formula and a₁ = - 7 , then

a₂ = 4a₁ = 4 (- 7) = - 28

a₃ = 4a₂ = 4(- 28) = - 112

a₄ = 4a₃ = 4(- 112) = - 448

a₅ = 4a₄ = 4(- 448) = - 1792

a₆ = 4a₅ = 4(- 1792) = - 7168

6 0
3 years ago
What is the percent as a fraction in lowest terms
Gwar [14]
1/100000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000 0000000000000000000000000000 etc.
4 0
3 years ago
Match the two numbers with their least common multiple (LCM).
timurjin [86]

Answer:

  • 8 and 4: A
  • 8 and 6: C
  • 8 and 10: B

Step-by-step explanation:

<u>8 and 4:</u>

Multiples of 8: 8, 16, 24

Multiples of 4: 4, 8, 12, 16

<u>8 and 6:</u>

Multiples of 8: 8, 16, 24

Multiples of 6: 6, 12, 18, 24

<u>8</u><u> </u><u>and</u><u> </u><u>10</u><u>:</u>

Multiples of 8: 8, 16, 24, 32, 40

Multiples of 10: 10, 20, 30, 40

4 0
3 years ago
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