Answer:
0.57142
Step-by-step explanation:
A normal random variable with mean and standard deviation both equal to 10 degrees Celsius. What is the probability that the temperature at a randomly chosen time will be less than or equal to 59 degrees Fahrenheit?
We are told that the Mean and Standard deviation = 10°C
We convert to Fahrenheit
(10°C × 9/5) + 32 = 50°F
Hence, we solve using z score formula
z = (x-μ)/σ, where
x is the raw score = 59 °F
μ is the population mean = 50 °F
σ is the population standard deviation = 50 °F
z = 59 - 50/50
z = 0.18
Probability value from Z-Table:
P(x ≤59) = 0.57142
The probability that the temperature at a randomly chosen time will be less than or equal to 59 degrees Fahrenheit
is 0.57142
Answer:
7+3(-4)(2)= -17
Step-by-step explanation:
7+3(-4)(2)
(-4)*2=-8
∴ 7+3(-8)= 7-24
= -17
Sent a picture of the solution to the problem (s).
Answer:
negative correlation on Edg
Step-by-step explanation:
On Thursday she cycled 88 km per hr...for 4 hrs
88/4 = 22 km per hr
On Friday, she cycled 3 km per hr faster
22 + 3 = 25 km per hr <==
