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Ksivusya [100]
3 years ago
5

What are the three steps you should use when using algebra to solve word problems?

Mathematics
1 answer:
KonstantinChe [14]3 years ago
3 0
Answer: understand , strategize and implement

Hoped it helped , if it didn’t I apologize
Good luck
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Surface area of a cube length: 10ft width: 7.5ft height: 12ft
Free_Kalibri [48]

Answer:

\large{\boxed{\bold{570  \ ft^2}}

Explanation:

Surface_Area_Cube: 2(Length x Width + Height x Length + Height x Width)

<h3 /><h3><u>Given sides</u>:</h3>
  • length: 10ft
  • width: 7.5ft
  • height: 12ft

<h3><u>Surface Area</u>:</h3>
  • 2(10 x 7.5 + 12 x 10 + 12 x 7.5)
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7 0
2 years ago
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Solve this question ​
ryzh [129]

Answer:

80

Step-by-step explanation:

Initial ratio:

Teachers to students

1 : 15

Ratio after:

Teachers to students

3 : 40

The number of students did not change, so we can make the students of the initial ratio and the students of the ratio after the same.

1 : 15 =  8 : 120

3 : 40 = 9 : 120

120 units = 1200

1 unit = \frac{1200}{120} =10

Initial teachers = 8 units = 8*10=80

7 0
3 years ago
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The table shows the results of a poll of 200 randomly selected juniors and seniors who were asked if they attended prom. Find th
Zielflug [23.3K]

Answer:

(a)\frac{7}{25}

(b)\frac{19}{116}

(c)\frac{28}{125}

Step-by-step explanation:

Number of juniors who attended prom,n(J)=28

Number of seniors who attended prom,n(S)=97

  • Total of those who attended prom=125

Number of juniors who did not attend prom,n(J')=56

Number of seniors who did not attend prom,n(S')=19

  • Total of those who attended prom=75
  • Total Number of students=200

(a) P (a junior who did not attend prom)

P(J')=\frac{56}{200}= \frac{7}{25}

(b)

P(Senior)=\frac{116}{200}

P ($did not attend prom$ | senior)=\frac{\text{P(seniors who did not attend prom)}}{P(Senior)} \\=\frac{19/200}{116/200} \\=\frac{19}{116}

(c)P (junior | attended prom)

P(Senior)=\frac{84}{200}

P (Junior|$ attended prom$)=\frac{\text{P(juniors who attended prom)}}{P(\text{those who attended prom)}} \\=\frac{28/200}{125/200} \\=\frac{28}{125}

3 0
3 years ago
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Polygons EFGH and E'F'G'H' are shown on the following coordinate grid:
vlabodo [156]
This would be modeled by a translation 1 unit down and a 270° clockwise rotation.

Each of these points has the x and y values switched, with the y value one less than that of the preimage and negated.  Taking one off the y-value is a translation 1 down; negating the y and switching it and x is a 270° clockwise rotation.
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Plzzzzz HELPPP WITH DIS LOOK AT THE PHOTO
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Vanessa can make 5 portions
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