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Ivahew [28]
3 years ago
8

What is pH?

Chemistry
1 answer:
Viktor [21]3 years ago
8 0
I think the answer A or C
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Calcium is a group 2 element. Chlorine is a group 7 element. They form an ionic compound called
kondaur [170]

Answer:

CaCl2

Explanation:

For every calcium there's 2 chlorine

7 0
3 years ago
How did the elements begin to stratify?
Bogdan [553]

Answer:

The process of elemental stratification relies on the diffusion velocity, which causes the migration of the different chemical elements within stars.

Explanation:

8 0
3 years ago
Engineers are starting on a new project to develop technology. Which of these
KATRIN_1 [288]

Answer:

D.

Explanation:

Deciding whether the best product has been designed,should be the last step.

3 0
3 years ago
A 0.533 g sample of a carbonate salt is added to a flask. The only thing you know is that per formula unit, there is only one ca
dimulka [17.4K]

Answer:

\mathbf{CrCO_3}

Explanation:

The total mole of H_2SO_4 added = 15 × 1 × 10⁻³

= 15 × 10⁻³ mole

= 15 mmoles

the number of moles of NaOH added in order to neutralize the excess acid = 0.5905 ×  29.393 = 17.36 mmoles

the equation for the reaction is:

2NaOH + H_2SO_4 --------> Na_2SO_4 +2H_2O

i.e

2 moles of NaOH react with H_2SO_4

1 moles of  NaOH will react with 1/2  H_2SO_4

17.36 mmoles of NaOH = 1/2 × 17.36 mmoles of H_2SO_4

                                       = 8.68 mmoles

Number of moles of H_2SO_4 that react with MCO₃ = Total moles of H_2SO_4 added - moles of H_2SO_4 reacted with NaOH

= (15 - 8.68) mmoles

= 6.32 mmoles

H_2SO_4 + MCO_3  ------>   M_2SO_4   +    H_2O   +   CO_2

1 mole of H_2SO_4 react with 1 mole of MCO_3

6.32 mmoles of H_2SO_4 = 6.32 mmoles of MCO_3

number of moles of MCO_3 = 6.32 10⁻³ moles

mass of  MCO_3 (carbonate salt) = 0.533 g

molar mass of MCO_3  = (M+60)g/mol

We all know that ;

number of moles = mass/molar mass

Then:

6.32 10⁻³ = 0.533 / (M+60)

(M+60) = 0.533/ 6.32 10⁻³

M + 60 = 84.34

M = 84.34 - 60

M = 24.34

Thus the element with the atomic mass of 24.34 is Chromium

The chemical formula for the compound is :  \mathbf{CrCO_3}

6 0
3 years ago
I’m so confused on this one!
stellarik [79]

The correct answer is 1) Ag, Si, I₂

Ag or silver is a metal. Silver is a transition element which lies in the d-block of the periodic table.

Si or silicon is a metalloid. Silicon is a metalloid which lies in the p-block of the periodic table.

I₂ or iodine is a nonmetal. Iodine is a halogen which lies in group 17 of the periodic table. All halogens are nonmetals.

5 0
4 years ago
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