F(x)=4x+1
g(x)=x^2-5
(f . g)(x)=?
(f . g)(x) = f(x) . g(x) = (4x+1).(x^2-5)=(4x).(x^2)+(4x).(-5)+(1).(x^2)+(1).(-5)
(f . g)(x) = 4x^(1+2)-20x+x^2-5
(f . g)(x)=4x^3+x^2-20x-5
Answer: Option A. 4x^3+x^2-20x-5
Answer:
The value of 3 in that number is 3 hundredths
Answer:
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This is how i worked it out.
Good Luck
