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OLga [1]
3 years ago
5

given the equation of a circle x^2+y^2-10x+4y+13=0. find its center and radius. i am having trouble please help

Mathematics
1 answer:
alexandr402 [8]3 years ago
7 0
x^2+y^2-10x+4y+13=0\\
x^2-10x+25+y^2+4y+4-16=0\\
(x-5)^2+(y+2)^2=16\\\\
\hbox{center}=(5,-2)\\
r=4
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Given △QRS ~ △XYZ, what is the value of tan(Q)?
VladimirAG [237]
Since the triangles are similar the ratios of the lengths of corresponding sides are equal.

tan Q = opp/adj = RS/QS = YZ/XZ = 9/12 = 3/4
8 0
3 years ago
Read 2 more answers
Penelope determined the solutions of the quadratic function by completing the square. F(x) = 4x2 8x 1 –1 = 4x2 8x –1 = 4(x2 2x)
Ymorist [56]

By solving the quadratic equation using completing the square method we got that Penelope should have added 4 to both sides instead of adding 1.

<h3>What is quadratic equation ?</h3>

Any equation of the form ax^2+bx+c=0 where x is variable and a, b, and c are any real numbers where a ≠ 0 is called quadratic equation .

Given work of Penelope is

$$\begin{aligned}&f(x)=4 x^{2}+8 x+1 \\&-1=4 x^{2}+8 x \\&-1=4\left(x^{2}+2 x\right) \\&-1+1=4\left(x^{2}+2 x+1\right) \\&0=4(x+2)^{2} \\&0=(x+2)^{2} \\&0=x+2 \\&-2=x\end{aligned}$$

Now we can see that Penelope determined the solutions of the quadratic function by completing the square. so he must have been done as following

$$\begin{aligned}&f(x)=4 x^{2}+8 x+1 \\&-1=4 x^{2}+8 x \\&-1=4\left(x^{2}+2 x\right) \\&-1+4=4\left(x^{2}+2 x+1\right) \\&3=4(x+2)^{2} \\&\frac{3}{4} =x+2)^{2} \\&\frac{\pm\sqrt3}{2} =x+2 \\&\frac{-2\pm\sqrt3}{2} =x\end{aligned}$$

By solving the quadratic equation using completing the square method we got that Penelope should have added 4 to both sides instead of adding 1.

To learn more about quadratic equations visit : brainly.com/question/1214333

8 0
2 years ago
I need helppppp ughhhhhhh
GarryVolchara [31]
Wrong person I pay someone to do my math for me :)
7 0
3 years ago
HELP ME ASAP PLEASE IM REALLY STRESSED :c
sveta [45]

Answer:

0.3 miles.

Step-by-step explanation:

If it takes all 3 of them to get there in a mile then it will equal to 3 miles.

5 0
3 years ago
Read 2 more answers
For a school fundraiser students are selling snack bags and candy bars to raise money on Wednesday the students or 23 snack bags
meriva

Answer:

$1.75

Step-by-step explanation:

The selling for each candy bar may be determined by  a set of linear equations. This pair of linear equations may be solved simultaneously by using the elimination method. This will involve ensuring that the coefficient of one of the unknown variables is the same in both equations.

It may be solved by substitution in that one of the variable is made the subject of the equation and the result is substituted into the second equation .

Let the cost of a snack bag be s and that of a candy bar be c, then if on Wednesday the students or 23 snack bags and 36 candy bars that raised $114.75 on Thursday the seventh so 37 snack bags and 36 candy bars that raised $146.25

23s + 36c = 114.75

37s + 36c = 146.25

14s = 31.5

s = $2.25

23(2.25) + 36c = 114.75

36c = 114.75 - 51.75

36c = 63

c = 63/36

= $1.75

3 0
3 years ago
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