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nirvana33 [79]
3 years ago
10

Which shows the following expression after the negative exponents have been eliminated?

Mathematics
2 answers:
belka [17]3 years ago
5 0

Answer:

The given expression  \frac{a^3}{ab^{-4}} after the negative exponents have been eliminated becomes \frac{a^3b^{4}}{ab^{2}}

Step-by-step explanation:

Given expression \frac{a^3b^{-2}}{ab^{-4}}

We have to write expression after the negative exponents have been eliminated and  a ≠ 0 and b ≠ 0.

Consider the given expression \frac{a^3b^{-2}}{ab^{-4}}  

We have to eliminate the negative exponents,

Using  property of exponents, x^{-m}=\frac{1}{x^m}  we have ,

b^{-2}=\frac{1}{b^2} \\\\b^{-4}=\frac{1}{b^4}

Substitute, we get,

\frac{a^3}{ab^{-4}} becomes  \frac{a^3b^{4}}{ab^{2}}

Thus, the given expression  \frac{a^3}{ab^{-4}} after the negative exponents have been eliminated becomes \frac{a^3b^{4}}{ab^{2}}

kipiarov [429]3 years ago
5 0

Answer:

option d

Step-by-step explanation:

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pshichka [43]

Answer:

a)Reflexive, not symmetric, transitive

b)Reflexive, not symmetric, transitive

c)Not reflexive, symmetric, not transitive

d)Reflexive, not symmetric, transitive

Step-by-step explanation:

a)

R=\left \{ (a,b)\epsilon  \mathbb{R} \times \mathbb{R} \mid a \leq b\right \}

The relation R is reflexive for

a\leq a for every real number a

it is not symmetric because 0 is less than 1, but 1 is not less than 0

it is transitive

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So if aRb and bRc, then aRc

b)  

R=\left \{ (m,n)\epsilon  \mathbb{Z} \times \mathbb{Z} \mid \exists k\in \mathbb{Z} \ni m=kn \right \}

R is reflexive because m=1.m for every integer m

R is not symmetric: 2 is a factor of 4, but 4 is not a factor of 2

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c)

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R is symmetric: if a different to b, then b different to a

R is not transitive: 1R2 and 2R1 (because 1 different to 2), but 1 = 1

d)

R=\left \{ A,B\mid A\subseteq B \right \}

R is reflexive for every set A is a subset of itself

R is not symmetric {1,2} is a subset of {1,2,3} but {1,2,3} is not a subset of {1,2}

R is transitive: if A is subset of B and B is subset of C, then A is subset of C

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Answer:


Step-by-step explanation:

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Answer:

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Answer:

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