Answer:
She increased 80% the practise time
Step-by-step explanation:
The question is incomplete, the following is missing:
<em>by how much did she increase the time she practised each day?
</em>
From Monday to Wednesday she increased 90 - 50 = 40 minutes the practise time.
To compute the increment as a percentage use: increment/reference *100
In this case, that is: 40/50*100 = 80%, where 50 minutes is taken as a reference.
1/2 fraction of whole carton was used for each serving
Answer:
13 l of 15%, 13 l of 25%, 26 l of 70%
Step-by-step explanation:
solutions:
final solution:
This includes 0.45*52l= 23.4 l acid
Let's assume:
- amount of 15% solution= x
- amount of 25% solution= y
- amount of 70% solution= z
- and we have z=2y
so there are 2 equation:
or
- x+y+2y= 52 ⇒ x+3y= 52 ⇒ x= 52- 3y
- 0.15x+1.65y=23.4
- 0.15*(52-3y)+1.65y=23.4
- 7.8-0.45y+1.65y=23.4
- 1.2y=23.4-7.8
- 1.2y= 15.6
--------
- x= 52- 3*13= 13 l
- z= 2y= 2*13= 26 l
Mean is the same as the average
median is the middle number
mode is the number that is used most often
range is the highest number minus the lowest number
example :
2,3,3,5,7
u find the mean by adding up all the numbers, then dividing by how many numbers there are. (2 + 3 + 3 + 5 + 7) / 5 = 20/5 = 4 (the mean)
the median would be the middle number, and that would be 3
the mode would be the number that appears the most..that would be 3 because it appears twice.
the range is the highest - lowest : 7 - 2 = 5 (the range)...bur dont get this confused by the interquartile range..it is not the same as the range.
