From the identity:
the inverse of f is g such that f(g(x))=x,
we must find g(x), such that![\frac{1}{cos[g(x)]}=x](https://tex.z-dn.net/?f=%20%5Cfrac%7B1%7D%7Bcos%5Bg%28x%29%5D%7D%3Dx%20)
thus,![cos[g(x)]= \frac{1}{x}](https://tex.z-dn.net/?f=cos%5Bg%28x%29%5D%3D%20%5Cfrac%7B1%7D%7Bx%7D%20)
Answer: b. g(x)=cos^-1(1/x)
the inverse of f is g such that f(g(x))=x,
we must find g(x), such that
thus,
Answer: b. g(x)=cos^-1(1/x)
In a 3-digit number, the hundreds is one more than the ones digit and tens digit is twice the hundred digit. If the the sum of t
1 answer:
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Answer:
<em>See attached</em>
<u>x- intercepts</u>
- (-2, 0), (-1, 0), (1, 0)
<u>y- intercept</u>
- (0, -2)
