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2 years ago

9

What are the solutions of 4x+8

align="absmiddle" class="latex-formula">-20

1 answer:

Fynjy0 [20]2 years ago

4 0

Answer: x≤−7

Step-by-step explanation:

hope that helps

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If 2/9 of the students in a school are in 6th grade, then how

sveticcg [70]

Answer:

231

Step-by-step explanation:

$\frac{2}{9}$ = $\frac{42}{x}$

42÷2= 21

9×21= 189

189 students total

42 6th graders

5 0

3 years ago

Read 2 more answers

What is the radical form of each of the given expressions?

IceJOKER [234]

1: square root of 2
2: cube root of 2, squared
3: square root of 3, squared
4: cube root of 3

hopefully this helps you :)

6 0

3 years ago

Terri is rewriting 7 Superscript 13 in expanded form. How many factors should she use in her expression?

netineya [11]

Answer:

7 x 13 expanded form is y = 7 x 13 ........ 7 dived by 13 in expand form is y=7 dived by 3

Step-by-step explanation:

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8 0

3 years ago

Find the value of x.

Lemur [1.5K]

Answer:

137

Step-by-step explanation:

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2 years ago

HELP!!<br>Find the third term of (x^2+3y)^3

lana66690 [7]

Answer:

$T_{3}=27{x}^{2}y^2$

Step-by-step explanation:

The given binomial expression is:

$( {x}^{2} + 3y)^{3}$

When we compare to:

${(a +b)}^{n}$

We have

$a = {x}^{2}$

$b = 3y \\ n = 3$

The nth term is given by;

$T_{r+1}=^nC_ra^{n-r}b^r$

To find the 3rd term, we put:

$r + 1 = 3 \\ r = 2$

We substitute into the formula to get:

$T_{3}=^3C_2( {x}^{2} )^{3-2}(3y)^2$

We simply:

$T_{3}=3( {x}^{2} )^{1} \times 9y^2$

$T_{3}=27{x}^{2}y^2$

3 0

3 years ago