0000000000000000000000000000000
x =2 y =8
2x + 2y=20
2x=20-2y
x=10-y
Ahora len la otra ecuacion remplazamos x por (10-y)
-2(10-y)-6y=-52
-20+2y-6y=-52
2y-6y= -32 (-52+20= -32)
-4y=-32
-y=-8
y=8 x=10-y x=2
2*2+2*8=20
4+16=20
-2*2-6*8= -52
-4-48= -52
Rewrite the boundary lines <em>y</em> = -1 - <em>x</em> and <em>y</em> = <em>x</em> - 1 as functions of <em>y </em>:
<em>y</em> = -1 - <em>x</em> ==> <em>x</em> = -1 - <em>y</em>
<em>y</em> = <em>x</em> - 1 ==> <em>x</em> = 1 + <em>y</em>
So if we let <em>x</em> range between these two lines, we need to let <em>y</em> vary between the point where these lines intersect, and the line <em>y</em> = 1.
This means the area is given by the integral,

The integral with respect to <em>x</em> is trivial:

For the remaining integral, integrate term-by-term to get

Alternatively, the triangle can be said to have a base of length 4 (the distance from (-2, 1) to (2, 1)) and a height of length 2 (the distance from the line <em>y</em> = 1 and (0, -1)), so its area is 1/2*4*2 = 4.
Answer:
-12
Step-by-step explanation:
(-4) - 8
Keep Flip Change
Keep
(-4)
Flip
- to +
Change to opposite
8 to -8
Result
-4 + -8 = -12