What are the roots of 4x2 + 35x − 9 = 0?

hichkok12 [17]

Answer:

You don't really need to do it, but it helps you keep things more organized and easier to follow. Imagine if you're doing some multi-variable equation,

2a + 5b + 4d + 3c + b + a + 2d

that looks like a mess, it'll be easier to look at if you put all the similar variables next to each others like this:

a + 2a + b + 5b + 3c + 2d + 4d

(a + 2a) + (b + 5b) + 3c + (2d + 4d)

now you can add them up much easier.

8 0

3 years ago

How do I find the distance of this?

zysi [14]

The formula is speed × time

4 0

3 years ago

Read 2 more answers

A local cell phone company charges $10.95 per month plus $0.15 per minute of anytime used.

Korolek [52]

Answer:

1.6425

Step-by-step explanation:

4 0

3 years ago

When f(x) = -3, what is x?

kap26 [50]

The letter "x" is often used in algebra to mean a value that is not yet known. It is called a "variable" or sometimes an "unknown". In x + 2 = 7, x is a variable, but we can work out its value if we try!

Hope this helps

4 0

3 years ago

PLEASE HELP! WILL MARK BRAINLIEST!

makkiz [27]

Answer:

The maximum height a rider will experience is 55 feet.

Step-by-step explanation:

Let's start writing the function that defines the path of a seat on the new Ferris wheel. This function will depend of the variable ''t'' which is time.

$X(t)=(x,y)$

In which $X(t)$ are the coordinates of the seat (the x - coordinate and the y - coordinate) that depend from time.

$''x''$ and $''y''$ are functions that depend from the variable ''t''.

For this exercise :

$X(t)=[-25sin(\frac{\pi}{30}t);-25cos(\frac{\pi}{30}t)+30]$

In order to find the maximum height a rider will experience we will study the behaviour of the y - component from the function $X(t)$ .

The function to study is $y(t)=-25cos(\frac{\pi}{30}t)+30$

To find its maximum, we will derivate this function and equalize it to 0. Doing this, we will find the ''critical points'' from the function.

⇒ $y(t)=-25cos(\frac{\pi}{30}t)+30$ ⇒

$y'(t)=\frac{5}{6}\pi sin(\frac{\pi}{30}t)$

Now we equalize $y'(t)$ to 0 ⇒

$y'(t)=0$ ⇒ $\frac{5}{6}\pi sin(\frac{\pi}{30}t)=0$

In this case it is easier to look for the values of ''t'' that verify :

$sin(\frac{\pi}{30}t)=0$

Now we need to find the values of ''t''. We know that :

$sin(0)=0\\\\sin(\pi)=0\\sin(-\pi)=0$

Therefore we can write the following equivalent equations :

$\frac{\pi}{30}t=0$ (I)

$\frac{\pi}{30}t=\pi$ (II)

$\frac{\pi}{30}t=-\pi$ (III)

From (I) we obtain $t_{1}=0$

From (II) we obtain $t_{2}=30$

And finally from (III) we obtain $t_{3}=-30$

We found the three critical points of $y(t)$ . To see if they are either maximum or minimum we will use the second derivative test. Let's calculate the second derivate of $y(t)$ :