Answer:
The answer is below
Step-by-step explanation:
The question is not complete. A complete question is in the form:
A letter is chosen at random from the letters of the word EXCELLENT. Find the probability that letter chosen is i) a vowel ii) a consonant.
Solution:
The total number of letters found in the word EXCELLENT = 9
i) The number of vowel letters found in the word EXCELLENT = {E, E, E} = 3
Hence, probability that letter chosen is a vowel = number of vowels / total number of letters = 3 / 9 = 1 / 3
probability that letter chosen is a vowel = 1/3 = 0.333 = 33.3%
ii) The number of consonant letters found in the word EXCELLENT = {X, C, L, L, N, T} = 6
Hence, probability that letter chosen is a consonant = number of consonant / total number of letters = 6 / 9 = 2 / 3
probability that letter chosen is a consonant = 2/3 = 0.667 = 66.7%
Answer:
x=b/(ay)
Step-by-step explanation:
To make x the subject of the formula, we basically have to isolate the x.
To do this we first multiply both sides by x.
xy=b/a
Now, to isolate the x, we simply divide by y,
x=b/(ay)
So x=b/(ay) is our answer
if the degree of the expression of the numerator is greater than that of the denominator, the rational expression has no horizontal asymptote.
Answer:
si
Step-by-step explanation:
