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MatroZZZ [7]
3 years ago
7

The distance between two asteroids was calculated at 37,500,000,000 kilometers. What is this value expressed in scientific notat

ion?
Mathematics
1 answer:
Shkiper50 [21]3 years ago
3 0
I believe that the answer is 3.75x10^10
You might be interested in
X^-9*x^-2 <br> a 1/x^18<br> b 1/x^11<br> c x^18<br> d x^11
d1i1m1o1n [39]
Exponent rule : a^-x = 1/a^x

x^-9 * x^-2 = 
1/x^9 * 1/x^2 = (when multiplying exponents with same base, add exponents)
1/x^(9 + 2) =
1/x^11

4 0
3 years ago
Which phase best describes the transition from the graph y=2x^2 to the graph of y2x^2+5?
Gre4nikov [31]

Answer:

Anything after x determines if it goes up since it's a positive 5 it's 5 units up

8 0
3 years ago
29. Fifty percent of the parallelogram is shaded. What is the area of the shaded region?
Butoxors [25]

Answer:

25 cm

Step-by-step explanation:

the whole parallelograph is 5 times 10 which equals 50. Devide that by 2 and you get 25

5 0
3 years ago
Read 2 more answers
Determine if the given ordered pair is a solution to the equation. Show work full.
sleet_krkn [62]

Answer:

The ordered pair is not a solution of the equation

Step-by-step explanation:

we know that

If a ordered pair is a solution of a linear equation, then the ordered pair must satisfy the linear equation

we have

y=-3x-13

Substitute the value of x and the value of y of the given ordered pair in the linear equation and analyze the results

For x=-1, y=15

15=-3(-1)-13

15=3-13

15=-10 ----> is not true

so

the ordered pair not satisfy the equation

therefore

The ordered pair is not a solution of the equation

5 0
3 years ago
What is the surface area and what do I need to do?
kari74 [83]

check the picture below, that's pretty much the same block, or "rectangular prism", with a width of 10, length of 5 and height of 1.


so anyhow, is really 6 rectangles stacked up to each other at the edges, so, we can simply get the area of each of those rectangles, add them up and that's the surface area.


front and back, two rectangles of  5x1

left and right, two rectangles of 1x10

top and bottom, two rectangles of 10x5


\bf \stackrel{\textit{front and back}}{2(5\cdot 1)}+\stackrel{\textit{left and right}}{2(1\cdot 10)}+\stackrel{\textit{top and bottom}}{2(10\cdot 5)}

5 0
3 years ago
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