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tensa zangetsu [6.8K]
4 years ago
5

Can someone answer this question please answer it correctly if it’s corect I will mark you brainliest

Mathematics
1 answer:
Daniel [21]4 years ago
3 0

Answer:

getting the queen is smaller

5/8

Step-by-step explanation:

There are 4 queens in a 52 card deck

P(queen) = 4/52 = 1/13

There are 12 pairs socks, 3 of which are grey

P(grey socks) = 3/12 = 1/4

1/13 <1/4

So getting a queen is smaller

The possible outcomes

8 +0  9+0   10+0  <em> 11+0</em>

8+1    9+1 <em>    10+1    11+1</em>

8+2<em>   9+2     10+2    11+2</em>

<em>8+3   9+3     10+3    11+3</em>

There are 16 outcomes and 10 of them are after 11, (assuming we add the time to the bedtime)

P (bedtime later than 10) = 10/16 = 5/8

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A taxicab starts at (1, -2) on the grid. It goes 3 blocks east and 1 block south to pick up a passenger. Then it goes 6 blocks w
elena-14-01-66 [18.8K]
(x,y)
east is an increase in x
west is a decrease in x
north is an increase in y
south is a decrease in y

so
3 east (x+3)
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basically x-3 and y+4
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8 0
4 years ago
Consider the following. C: counterclockwise around the triangle with vertices (0, 0), (1, 0), and (0, 1), starting at (0, 0)
horsena [70]

Answer:

a.

\mathbf{r_1 = (t,0)  \implies  t = 0 \ to \ 1}

\mathbf{r_2 = (2-t,t-1)  \implies  t = 1 \ to \ 2}

\mathbf{r_3 = (0,3-t)  \implies  t = 2 \ to \ 3}

b.

\mathbf{\int  \limits _{c} F \ dr =\dfrac{11 \sqrt{2}+11}{6}}

Step-by-step explanation:

Given that:

C: counterclockwise around the triangle with vertices (0, 0), (1, 0), and (0, 1), starting at (0, 0)

a. Find a piecewise smooth parametrization of the path C.

r(t) = { 0

If C: counterclockwise around the triangle with vertices (0, 0), (1, 0), and (0, 1),

Then:

C_1 = (0,0) \\ \\  C_2 = (1,0) \\ \\ C_3 = (0,1)

Also:

\mathtt{r_1 = (0,0) + t(1,0) = (t,0) }

\mathbf{r_1 = (t,0)  \implies  t = 0 \ to \ 1}

\mathtt{r_2 = (1,0) + t(-1,1) = (1- t,t) }

\mathbf{r_2 = (2-t,t-1)  \implies  t = 1 \ to \ 2}

\mathtt{r_3 = (0,1) + t(0,-1) = (0,1-t) }

\mathbf{r_3 = (0,3-t)  \implies  t = 2 \ to \ 3}

b Evaluate :

Integral of (x+2y^1/2)ds

\mathtt{\int  \limits ^1_{c1} (x+ 2 \sqrt{y}) ds = \int  \limits ^1_{0} \ (t + 0)  \sqrt{1} } \\ \\ \mathtt{  \int  \limits ^1_{c1} (x+ 2 \sqrt{y}) ds = \begin {pmatrix} \dfrac{t^2}{2} \end {pmatrix} }^1_0 \\ \\  \mathtt{\int  \limits ^1_{c1} (x+ 2 \sqrt{y}) ds = \dfrac{1}{2}}

\mathtt{\int  \limits _{c2} (x+ 2 \sqrt{y}) ds = \int  \limits (x+2 \sqrt{y} \sqrt{(\dfrac{dx}{dt})^2 + (\dfrac{dy}{dt})^2 \ dt } }

\mathtt{\int  \limits _{c2} (x+ 2 \sqrt{y}) ds = \int  \limits 2- t + 2\sqrt{t-1}  \ \sqrt{1+1}  }

\mathtt{\int  \limits _{c2} (x+ 2 \sqrt{y}) ds =  \sqrt{2} \int  \limits^2_1  2- t + 2\sqrt{t-1} \ dt }

\mathtt{\int  \limits _{c2} (x+ 2 \sqrt{y}) ds =  \sqrt{2}  }  \ \begin {pmatrix} 2t - \dfrac{t^2}{2}+ \dfrac{2(t-1)^{3/2}}{3} (2)  \end {pmatrix} ^2_1}

\mathtt{\int  \limits _{c2} (x+ 2 \sqrt{y}) ds =  \sqrt{2}  }  \ \begin {pmatrix} 2 -\dfrac{1}{2} (4-1)+\dfrac{4}{3} (1)^{3/2} -0 \end {pmatrix} }

\mathtt{\int  \limits _{c2} (x+ 2 \sqrt{y}) ds =  \sqrt{2}  }  \ \begin {pmatrix} 2 -\dfrac{3}{2} + \dfrac{4}{3} \end {pmatrix} }

\mathtt{\int  \limits _{c2} (x+ 2 \sqrt{y}) ds =  \sqrt{2}  }  \ \begin {pmatrix} \dfrac{12-9+8}{6} \end {pmatrix} }

\mathtt{\int  \limits _{c2} (x+ 2 \sqrt{y}) ds =  \sqrt{2}  }  \ \begin {pmatrix} \dfrac{11}{6} \end {pmatrix} }

\mathtt{\int  \limits _{c2} (x+ 2 \sqrt{y}) ds =   \dfrac{ \sqrt{2}  }{6} \  (11 )}

\mathtt{\int  \limits _{c2} (x+ 2 \sqrt{y}) ds =   \dfrac{ 11 \sqrt{2}  }{6}}

\mathtt{\int  \limits _{c3} (x+ 2 \sqrt{y}) ds =  \int  \limits ^3_2 0+2 \sqrt{3-t}   \ \sqrt{0+1} }

\mathtt{\int  \limits _{c3} (x+ 2 \sqrt{y}) ds =  \int  \limits ^3_2 2 \sqrt{3-t}   \ dt}

\mathtt{\int  \limits _{c3} (x+ 2 \sqrt{y}) ds =  \int  \limits^3_2 \begin {pmatrix}  \dfrac{-2(3-t)^{3/2}}{3} (2) \end {pmatrix}^3_2 }

\mathtt{\int  \limits _{c3} (x+ 2 \sqrt{y}) ds = -\dfrac{4}{3} [(0)-(1)]}

\mathtt{\int  \limits _{c3} (x+ 2 \sqrt{y}) ds = -\dfrac{4}{3} [-(1)]}

\mathtt{\int  \limits _{c3} (x+ 2 \sqrt{y}) ds = \dfrac{4}{3}}

\mathtt{\int  \limits _{c} F \ dr =\dfrac{11 \sqrt{2}}{6}+\dfrac{1}{2}+ \dfrac{4}{3}}

\mathtt{\int  \limits _{c} F \ dr =\dfrac{11 \sqrt{2}+3+8}{6}}

\mathbf{\int  \limits _{c} F \ dr =\dfrac{11 \sqrt{2}+11}{6}}

5 0
3 years ago
Plz help me answer this question
Oksana_A [137]

Answer:

The answer to your question is distance = 3500000 km

Step-by-step explanation:

Data

Scale  1 : 500000

7 cm

Process

1.- To solve this problem use direct proportions or rule of three.

                          1 : 500 000 :: 7 : x

2.- Multiply the middle numbers and the result divide it by the edge.

                x = (7 x 500000) / 1

Simplification

                x = 3500000 km                            

7 0
4 years ago
Please give me this answe
nordsb [41]
Five to the power of 10 would be 9765625, so the scientific notation would be
9.765625 * (10^6), I think.

(I haven't done scientific notation in a long time, but I'm relatively sure that is what it is.)

Hope this kind of helped!
7 0
3 years ago
Read 2 more answers
Classify 8 and 0.25 rational, integers, or whole number pls
Eddi Din [679]
8 and .25 are rational numbers because integers are negative and whole numbers don't include decimals and rational numbers can include whole number like 8 or 8/1 and .25.
5 0
4 years ago
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