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Natalija [7]
3 years ago
7

What's the Answer I need help quick!!!

Mathematics
2 answers:
Ganezh [65]3 years ago
7 0
It would be A because that is the opposite of the given equation 
Rom4ik [11]3 years ago
4 0
C?------------------------
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How do I answer this question?
ankoles [38]
It's 78.38
You have to square root
8 0
3 years ago
Suppose X, Y, and Z are random variables with the joint density function f(x, y, z) = Ce−(0.5x + 0.2y + 0.1z) if x ≥ 0, y ≥ 0, z
dexar [7]

Answer:

The value of the constant C is 0.01 .

Step-by-step explanation:

Given:

Suppose X, Y, and Z are random variables with the joint density function,

f(x,y,z) = \left \{ {{Ce^{-(0.5x + 0.2y + 0.1z)}; x,y,z\geq0  } \atop {0}; Otherwise} \right.

The value of constant C can be obtained as:

\int_x( {\int_y( {\int_z {f(x,y,z)} \, dz }) \, dy }) \, dx = 1

\int\limits^\infty_0 ({\int\limits^\infty_0 ({\int\limits^\infty_0 {Ce^{-(0.5x + 0.2y + 0.1z)} } \, dz }) \, dy } )\, dx = 1

C\int\limits^\infty_0 {e^{-0.5x}(\int\limits^\infty_0 {e^{-0.2y }(\int\limits^\infty_0 {e^{-0.1z} } \, dz  }) \, dy  }) \, dx = 1

C\int\limits^\infty_0 {e^{-0.5x}(\int\limits^\infty_0{e^{-0.2y}([\frac{-e^{-0.1z} }{0.1} ]\limits^\infty__0 }) \, dy  }) \, dx = 1

C\int\limits^\infty_0 {e^{-0.5x}(\int\limits^\infty_0 {e^{-0.2y}([\frac{-e^{-0.1(\infty)} }{0.1}+\frac{e^{-0.1(0)} }{0.1} ])  } \, dy  }) \, dx = 1

C\int\limits^\infty_0 {e^{-0.5x}(\int\limits^\infty_0 {e^{-0.2y}[0+\frac{1}{0.1}]  } \, dy  }) \, dx =1

10C\int\limits^\infty_0 {e^{-0.5x}([\frac{-e^{-0.2y} }{0.2}]^\infty__0  }) \, dx = 1

10C\int\limits^\infty_0 {e^{-0.5x}([\frac{-e^{-0.2(\infty)} }{0.2}+\frac{e^{-0.2(0)} }{0.2}]   } \, dx = 1

10C\int\limits^\infty_0 {e^{-0.5x}[0+\frac{1}{0.2}]  } \, dx = 1

50C([\frac{-e^{-0.5x} }{0.5}]^\infty__0}) = 1

50C[\frac{-e^{-0.5(\infty)} }{0.5} + \frac{-0.5(0)}{0.5}] =1

50C[0+\frac{1}{0.5} ] =1

100C = 1 ⇒ C = \frac{1}{100}

C = 0.01

3 0
3 years ago
Law of Sines or Law of Cosines....Help!!
iren2701 [21]

Answer:

Law of cosines to find missing measures

c^2= a^2+ b^2 - 2ab*cos(C)

Used because it is a SAS triangle

Step-by-step explanation:

This is known as a side, angle, side, or SAS triangle. We can find the missing measures by using the Law of cosines

c^2= a^2+b^2-2ab*cos(C)

7 0
3 years ago
What is the approximate area of a circle with a radius of 13cm? A.40.8cm² B.530.7cm² C.784cm² D.2461.8cm²
Gnesinka [82]
It would be B (530.7) because if you do 3.14 x 13 x 13 (Or to the second power) Then you get 530.66, the round to the nearest tenths 
4 0
3 years ago
Read 2 more answers
Two events, A and B, are independent of each other. P(A) = 1/6 and P(A and B) = 1/8 What is P(B) written as a decimal? Round to
Leona [35]
P(B) = 0.75.

For independent events, P(A and B) = P(A)*P(B).  This gives us

1/8 = 1/6(x)

Divide both sides by 1/6:
1/8 ÷ 1/6 = x
1/8 × 6/1 = x
6/8 = x
3/4 = x
0.75 = x
5 0
3 years ago
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