Find the dicontinuities of the function. f(x) = x2 + 12x + 27 x2 + 4x + 3 . There is a removable discontinuity at (, ).

Mathematics

2 answers:

ollegr [7]3 years ago

5 0

Answer:

Step-by-step explanation:

its -3 -3 for both

ValentinkaMS [17]3 years ago

4 0

Solution-

$f(x)=\frac{x^{2}+12x+27 }{x^{2} +4x+3} =\frac{x^{2}+9x+3x+27 }{x^{2} +3x+x+3}=\frac{(x+3)(x+9)}{(x+3)(x+1)}$

Equating the denominator to 0,

⇒ (x+3)(x+1) = 0

⇒ x= -3, -1

∴ Discontinuities of the function f(x) is at -3, -1

As (x+3) is also a factor of the numerator, you will have what's called a removable discontinuity. That will show up as a hole in the graph.

∴ At x = -3, you will have removable discontinuity.

You might be interested in

The table below represents the amount that Christian pays for cable service. Predict how much he will pay for 5 months of cable

Amiraneli [1.4K]

300 would be the answer

3 0

3 years ago

A study was recently conducted to estimate the mean cholesterol for adult males over the age of 55 years. From a random sample o

Komok [63]

Answer: Correct critical value = 2.2622

Step-by-step explanation:

Confidence interval for population mean when population standard deviation is unknown:

$\overline{x}\pm t_{\alpha/2}\dfrac{s}{\sqrt{n}}$ , where $\overline{x}$ = sample mean, n= sample size, s= sample standard deviation, $t_{\alpha/2}$ = two-tailed t value.

As per given: n= 10

degree of freedom : df = n-1=9

$\overline{x}=242.6\\\\s=73.33\\\\\alpha=5\%=0.05$

Critical t-value : $t_{\alpha/2,df}=t_{0.05/2,9}=t_{0.025,9}=2.2622$

So, the 95 percent confidence interval estimate for the mean :

$242.6\pm (2.2622)\dfrac{73.33}{\sqrt{10}}\\\\=242.6\pm (2.2622)(23.19)\\\\\approx242.6\pm52.46\\\\=(242.6-52.46,\ 242.6+52.46)\\\\=(190.14,\ 295.06)$