Find the dicontinuities of the function. f(x) = x2 + 12x + 27 x2 + 4x + 3 . There is a removable discontinuity at (, ).
2 answers:
Solution-
Equating the denominator to 0,
⇒ (x+3)(x+1) = 0
⇒ x= -3, -1
∴ Discontinuities of the function f(x) is at -3, -1
As (x+3) is also a factor of the numerator, you will have what's called a removable discontinuity. That will show up as a hole in the graph.
∴ At x = -3, you will have removable discontinuity.
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