All categories

3 years ago

A newborn weighs 8 pounds, 5 ounces. There are 453.59 grams per pound. What is the infant's weight in grams?

Mathematics

1 answer:

Nadya [2.5K]3 years ago

5 0

Convert from Oz and Lbs.

1 Pound = 453.59237 Grams

1 Ounce = 28.3495231 Grams

3628.73896 for Lbs

141.7476155 for Oz

Add them, and you get:

3770.4865755

I didn't know if you needed rounding - it was classified as college.

Hope this helped, and have a good day!

You might be interested in

Select linear or nonlinear to correctly classify each function.

cluponka [151]

Answer:

1: Linear

2: Nonlinear

3: Nonlinear

4: Linear

8 0

3 years ago

Read 2 more answers

How do I answer this dot plot?

Anna11 [10]

It would seem the problem requires you compute the mean, median, and standard deviation of each of the data sets. This is nicely done using the statistics functions of your graphing calculator.

Data Set A (mean, median, standard deviation) = (29.7, 29.5, √12.71)
Data Set B (mean, median, standard deviation) = (27.95, 27, √6.1475)

1. False. Data Set B is skewed to the right.
2. TRUE. 27.95 is within 3 of 29.7.
3. False. √12.71 ≠ √6.1475
4. False. The mean of Data Set A is 29.7.
5. False. Data Set A has the higher standard deviation.
6. TRUE. 29.7 is close to 29.5.

The true statements are
• the 2nd one
• the 6th one

3 0

3 years ago

Sarah is paid $20 an hour at her new job. She wishes to graph her total pay y, as a function of the

icang [17]

Answer:

see image; 200; 400

Step-by-step explanation:

y=20x

graph

6 0

3 years ago

In 2010, the average duration of long-distance telephone calls originating in one town was 9.4 minutes. A long-distance telephon

Zepler [3.9K]

<u>Answer</u>: No, we do not have sufficient evidence to conclude that the mean call duration, µ, is different from the 2010 mean of 9.4 minutes.

Step-by-step explanation:

As per given , we have

$H_0: \mu=9.4\\\\H_a:\mu\neq9.4$ , since $H_0$ is two-tailed so , the test is a two tail test.

Since population standard deviation is unknown, so we use t-test.

Critical value (two-tailed) for significance level of 0.01= $t_{n-1,\alpha/2}=t_{49, 0.005}\pm2.609228$

For n =50 , $\overline{x}=8.6$ and s= 4.8

Test statistic : $t=\dfrac{\overline{x}-\mu}{\dfrac{s}{\sqrt{n}}}$

$t=\dfrac{8.6-9.4}{\dfrac{4.8}{\sqrt{50}}}\approx-1.18$

Since test statistic value (-1.18) lies in critical interval (-2.609228, 2.609228), it means the null hypothesis is failed to reject.

We do not have sufficient evidence to conclude that the mean call duration, µ, is different from the 2010 mean of 9.4 minutes.

4 0

3 years ago

Zepler [3.9K]

It took 12 days for all the 60 gallons of water to leak out of the barrel. If you divide 60 by 5 you will get 12.

4 0

3 years ago

Read 2 more answers