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3 years ago

What is the value of x?

Mathematics

1 answer:

barxatty [35]3 years ago

3 0

Answer:

Step-by-step explanation:

x² = 40² + 9²

= 1600 + 81

x² = 1681

x = √1681

x= 41

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Solve for x: please help

valina [46]

Answer:

45 because an acute angle is 45 degrees

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3 years ago

Read 2 more answers

Joel earns $5.50 an hour and time-and-a-half for overtime. how much does he earn for a 44.5-hour week?

vova2212 [387]

The expression which can be used to solve this problem is 5.50h + 1.5h.

Since the given data is 44.5 hour week, all we need to do is substitute the given data to the expression. Since it takes 56 hours a week for a complete office/working hour without overtime, Joel's 44.5 hour week means he did not have overtime hours. Therefore the solution is,

5.50(44.5) = 244.75 Dollars.

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3 years ago

Should one divulge information given in confidence

pickupchik [31]

No you should not do that.

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3 years ago

How to find the length

Zinaida [17]

Answer:

1. √32

2. 4

3. 5

4. √29

5. √10

6. 5√2

Step-by-step explanation:

Use Pythagoras

4 0

3 years ago

Scores on a test are normally distributed with a mean of 81.2 and a standard deviation of 3.6. What is the probability of a rand

Misha Larkins [42]

<u>Answer:</u>

The probability of a randomly selected student scoring in between 77.6 and 88.4 is 0.8185.

<u>Solution:</u>

Given, Scores on a test are normally distributed with a mean of 81.2

And a standard deviation of 3.6.

We have to find What is the probability of a randomly selected student scoring between 77.6 and 88.4?

For that we are going to subtract probability of getting more than 88.4 from probability of getting more than 77.6

Now probability of getting more than 88.4 = 1 - area of z – score of 88.4

$\mathrm{Now}, \mathrm{z}-\mathrm{score}=\frac{88.4-\mathrm{mean}}{\text {standard deviation}}=\frac{88.4-81.2}{3.6}=\frac{7.2}{3.6}=2$

So, probability of getting more than 88.4 = 1 – area of z- score(2)

= 1 – 0.9772 [using z table values]

= 0.0228.

Now probability of getting more than 77.6 = 1 - area of z – score of 77.6

$\mathrm{Now}, \mathrm{z}-\text { score }=\frac{77.6-\text { mean }}{\text { standard deviation }}=\frac{77.6-81.2}{3.6}=\frac{-3.6}{3.6}=-1$

So, probability of getting more than 77.6 = 1 – area of z- score(-1)

= 1 – 0.1587 [Using z table values]

= 0.8413

Now, probability of getting in between 77.6 and 88.4 = 0.8413 – 0.0228 = 0.8185

Hence, the probability of a randomly selected student getting in between 77.6 and 88.4 is 0.8185.

4 0

3 years ago