Hello!
We can write this as the system of equations below. We have boxes A, B, and C.
A+B+C=9
B=A+1
C=B+1
First of all we can plug our B and C values into the first equation and solve for A.
A+A+1+A+1+1=9
3a+3=9
3a=6
a=2
Now we can plug our a value into the other equations.
B=2+1
B=3
C=3+1
C=4
Therefore, there are 2 rocks in one box, three in another, and 4 in the last.
I hope this helps!
Answer:
1. 6
2. 2
Step-by-step explanation:
1. 9-t=3(t-5)
9-t=3t-15
+t +t
9=4t-15
+15 +15
<u>24</u>=<u>4t</u>
4 4
6=t
2.5(5y+1)=10y-25
25y+5=10y-25
+25 +25
25y+30=10y
-25 -25
<u>30</u>=<u>-15y</u>
15 15
2=y
Answer:
809.4cm²
Step-by-step explanation:
Given the following :
Systematic error = 3.8cm (The measured length is always more than the actual length.)
Most probable dimension :
Width = 85.7 cm
Length = 123.5 cm
Hence most probable area of Rectangle :
Area = Length × Width
Area = 85.7cm × 123.5cm = 10583.95 cm²
Dimension due to Systematic error :
Length = (85.7cm + 3.8cm) = 89.5cm
Width = (123.5cm + 3.8cm) = 127.3cm
Area = Length × width
Area = ( 89.5cm × 127.3) = 11393.35cm²
Systematic error of the area :
value of area with Systematic error - Probable value of area :
11393.35cm² - 10583.95 cm² = 809.4cm²
The cost of 1 adult ticket in the off season is 42$, but it is asking for the child ticket's price so you would do 194-42 and you get 152. Then, you would divide 152/4 and you get 38 but this is during the off-season so you would double it and get 76.
The regular price for a child is 76$
But feel free to check my work :D
For this problem, I believe you would just have to plug in for x.
For example, -17 divided by 10 and so on.
The answer should be C, -70. -70 divided by 10 equals -7.
