Question

Two values of x that are roots of xsquared+2x-6=0

Answer 1

The two values of x are

1.65 , -3.65

Answer 2

Answer:

Two values of x that are :

$x=-\sqrt{7}-1$

$x=\sqrt{7}-1$

Step-by-step explanation:

Given= $x^2+2x-6=0$

To find = Two values of x

Solution :

$x^2+2x-6=0$

Adding and subtracting 1 in the equation :

$x^2+2x+1-1-6=0$

$(x^2+2\times x\times 1+1^2)-1-6=0$

$(x+1)^2-7=0$

$(x+1)^2=7$

$(x+1)=\pm \sqrt{7}$

Two values of x that are :

$x=-\sqrt{7}-1$

$x=\sqrt{7}-1$